Yes. Think of y as being a function of x. y = f(x) = x2 + 1
Y=X^2 is a function for it forms a parabola on a graph.
x2+2x+1=y or y=x2 In this function the domain is x equals real values and the range is y equals all real values provided y is more than or equal to zero.
No, because there is more than one solution: y2 = x2 y = ±(x2)1/2 y = ±x Because there are multiple solutions for a single value of x, this does not qualify as a function.
6
(the shape is an upside down 'u').
x = -3y = -14
Implicit: x2 + 2y = 5 Explicit : y = (5 - x2)/2
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
It looks like a parabola which looks like a U shape.
The domain of y = x2 is [0,+infinity]
The "root" of a function is also called the "zero" of a function. This is where the function equals zero. The function y=4-x2 has roots at x=2 and x=-2 The function y=4-x2 has zeroes at x=2 and x=-2 Those are equivalent statements.