It is a injective relationship. However, it need not be surjective and so will not be bijective. It will, therefore, not define an invertible function.
Domain, codomain, range, surjective, bijective, invertible, monotonic, continuous, differentiable.
Assume that f:S->T is invertible with inverse g:T->S, then by definition of invertible mappings f*g=i(S) and g*f=i(T), which defines f as the inverse of g. So g is invertible.
Indeterminate. How? a4b5 is the expression instead of equality. Since we are not given the equality of two variables, there is no way to determine whether it's invertible or not. Otherwise, if you are referring "a" and "b" as invertible matrices, then yes it's invertible. This all depends on the details.
The answer depends on the context for opposite. Common opposites are the additive or multiplicative inverses but any invertible function can be used to define an opposite.
It is an invertible function.
No. If the function has more than one x-intercept then there are more than one values of x for which y = 0. This means that, for the inverse function, y = 0 should be mapped onto more than one x values. That is, the inverse function would be many-to-one. But a function cannot be many-to-one. So the "inverse" is not a function. And tat means the original function is not invertible.
It is a injective relationship. However, it need not be surjective and so will not be bijective. It will, therefore, not define an invertible function.
A one-to-one function, a.k.a. an injective function.
It is any invertible function.
What is "a 3b"? Is it a3b? or a+3b? 3ab? I think "a3b" is the following: A is an invertible matrix as is B, we also have that the matrices AB, A2B, A3B and A4B are all invertible, prove A5B is invertible. The problem is the sum of invertible matrices may not be invertible. Consider using the characteristic poly?
Domain, codomain, range, surjective, bijective, invertible, monotonic, continuous, differentiable.
Assume that f:S->T is invertible with inverse g:T->S, then by definition of invertible mappings f*g=i(S) and g*f=i(T), which defines f as the inverse of g. So g is invertible.
Here are some examples:Domain, codomain, range, surjective, bijective, invertible, monotonic, continuous, differentiable.
Indeterminate. How? a4b5 is the expression instead of equality. Since we are not given the equality of two variables, there is no way to determine whether it's invertible or not. Otherwise, if you are referring "a" and "b" as invertible matrices, then yes it's invertible. This all depends on the details.
The answer depends on the context for opposite. Common opposites are the additive or multiplicative inverses but any invertible function can be used to define an opposite.
Invertible counterpoint The contrapuntal design of two or more voices in a polyphonic texture so that any of them may serve as an upper voice or as the bass. Invertible counterpoint involving two (three, four) voices is called double (triple, quadruple) counterpoint. http://www.answers.com/topic/invertible-counterpoint-music