4 buses, 3 cars.
If the probability that a bus arrives on time 4 sevenths of a time, it means that for every 7 buses, 4 arrive on time. By deduction it also means that for every 7 buses 3 of them come late. If out of 7 buses 3 come late can you figure out how many buses out of 210 buses will be late based on the same probability? I am sure you can. Good luck!
buses
yes
Non
Buses can only legally carry a certain number of passengers. Therefore, the number of students could be restricted to the number of buses available, or the number of buses could be increased to cater for the full number of students. In some cases, 2 or 3 excess students could travel in a tutor's car.
Usually it is the other way around, but I suppose a skinflint school might insist that only one bus-load can go!
To find out how many students were in each bus, we first subtract the students who traveled in cars from the total number of students: 331 - 7 = 324 students. Then, we divide the remaining students by the number of buses to determine how many students were in each bus: 324 students / 6 buses = 54 students in each bus.
3 buses are needed for the fieldtrip, providing maximum capacity for 252 students.
48 students per bus times 65 buses = 3120 students(48x65=3120)
They'll need 9 buses. Buses #1 through #8 will be full. Bus #9 will have only 16 students on it.
The answer is 24 at least
Hi
most of the times...
With taxes yes. Free to students
Depends. Buses are usually designated by their function; i.e., tour buses, metro transit buses, school buses, etc. If you're thinking of the ones which are extra long and have a pivot point between the front and rear, those are articulated buses.
they don't listen