Yes. In general, if an integer is not a perfect square, its square root is irrational.
No.
sqrt 90 = sqrt 9 x sqrt 10 = 3 root 10. Root 10 is irrational so sqrt 90 is irrational.
-90 squared is rational - it is +8100. All perfect squares are not only rational but they are integers.
9.48683298 is the square root of 90
Yes. In general, if an integer is not a perfect square, its square root is irrational.
No, it is not.
No.
No.
Yes, they both are.
sqrt 90 = sqrt 9 x sqrt 10 = 3 root 10. Root 10 is irrational so sqrt 90 is irrational.
-90 squared is rational - it is +8100. All perfect squares are not only rational but they are integers.
9.48683Assuming you mean sqrt as in "square root" then sqrt(90)=9.48683298050513799596806332982.(that's as far as my calculator goes there's infinitely more digits)The square root of 90 is: 9.4868329805051The square root of 90 is 9.48683298, or 3√10 in simplest radical form.It is an irrational number which can be simplified to 3 times the square root of 10
square root of 90
The square root of 8100 is 90 (90 x 90 = 8100)
The square root of 1800 is 90
It's never been proven to be irrational, but I'm running it through an iterative precision program and so far I've got: 9.486832980505137995996680633298155601158665417975650480572514 It looks irrational up to its 60th decimal at least. Unfortunately, 60 is way less than infinity, so this really demonstrates nothing.