Yes. In general, if an integer is not a perfect square, its square root is irrational.
No.
sqrt 90 = sqrt 9 x sqrt 10 = 3 root 10. Root 10 is irrational so sqrt 90 is irrational.
-90 squared is rational - it is +8100. All perfect squares are not only rational but they are integers.
The square root of 90 times 10 can be calculated as follows: first, multiply 90 by 10 to get 900. Then, find the square root of 900, which is 30. Therefore, the square root of 90 times 10 is 30.
Yes. In general, if an integer is not a perfect square, its square root is irrational.
No, it is not.
No.
No.
Yes, they both are.
sqrt 90 = sqrt 9 x sqrt 10 = 3 root 10. Root 10 is irrational so sqrt 90 is irrational.
-90 squared is rational - it is +8100. All perfect squares are not only rational but they are integers.
9.48683Assuming you mean sqrt as in "square root" then sqrt(90)=9.48683298050513799596806332982.(that's as far as my calculator goes there's infinitely more digits)The square root of 90 is: 9.4868329805051The square root of 90 is 9.48683298, or 3√10 in simplest radical form.It is an irrational number which can be simplified to 3 times the square root of 10
square root of 90
The square root of 8100 is 90 (90 x 90 = 8100)
It's never been proven to be irrational, but I'm running it through an iterative precision program and so far I've got: 9.486832980505137995996680633298155601158665417975650480572514 It looks irrational up to its 60th decimal at least. Unfortunately, 60 is way less than infinity, so this really demonstrates nothing.
The square root of 1800 is 90