Given a set of n scores, the variance is sum of the squared deviation divided by n or n-1. We divide by n for the population and n-1 for the sample.
To calculate the mean absolute deviation (MAD) of Victoria's science scores, you first find the mean of her scores. Then, subtract the mean from each individual score to find the absolute deviations. Finally, calculate the average of these absolute deviations. Without the specific scores, I cannot provide a numerical answer, but this is the process to find the MAD.
In a normal distribution, approximately 95% of the scores fall within two standard deviations of the mean. This means that about 5% of the scores will be below two standard deviations above the mean. Therefore, if you have 100 scores, you can expect around 5 scores to be below 32.38.
In a normal distribution, approximately 68% of scores fall within one standard deviation of the mean (between -1 and +1 standard deviations). About 95% of scores fall within two standard deviations (between -2 and +2 standard deviations). Therefore, the percentage of scores that falls specifically between the mean and -2 to 2 standard deviations is about 95% minus the 50% that is below the mean, resulting in approximately 45%.
Average = (0+0+1+2+3)/5 = 1.2 Variance = 1/N * SUM (x-E(x))2 = 1/5 * 6.8 = 1.36 Answer: Variance = 1.36
In a normal distribution, approximately 99.7% of scores fall within three standard deviations of the mean, according to the empirical rule. This means that only about 0.3% of scores lie beyond three standard deviations from the mean—0.15% in each tail. Thus, scores more than three standard deviations above or below the mean are quite rare.
sum of scores: 24 mean of scores : 24/4 = 6 squared deviations from the mean: 9, 4,4,9 sum of these: 26 sample variance: 26/4 = 6.5
Variance
Variance
The standard deviation is defined as the square root of the variance, so the variance is the same as the squared standard deviation.
mean
The variance is: 6.0
To calculate the mean absolute deviation (MAD) of Victoria's science scores, you first find the mean of her scores. Then, subtract the mean from each individual score to find the absolute deviations. Finally, calculate the average of these absolute deviations. Without the specific scores, I cannot provide a numerical answer, but this is the process to find the MAD.
The variance is: 0.666666666667
In a normal distribution, approximately 95% of the scores fall within two standard deviations of the mean. This means that about 5% of the scores will be below two standard deviations above the mean. Therefore, if you have 100 scores, you can expect around 5 scores to be below 32.38.
In a normal distribution, approximately 68% of scores fall within one standard deviation of the mean (between -1 and +1 standard deviations). About 95% of scores fall within two standard deviations (between -2 and +2 standard deviations). Therefore, the percentage of scores that falls specifically between the mean and -2 to 2 standard deviations is about 95% minus the 50% that is below the mean, resulting in approximately 45%.
Average = (0+0+1+2+3)/5 = 1.2 Variance = 1/N * SUM (x-E(x))2 = 1/5 * 6.8 = 1.36 Answer: Variance = 1.36
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