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No, the y-intercept is not the same as the absolute value parent function. The absolute value parent function, represented as ( f(x) = |x| ), has a vertex at the origin (0, 0), which serves as its y-intercept. While the absolute value function does have a specific y-intercept, the term "y-intercept" generally refers to the point where any function crosses the y-axis, which can vary depending on the function in question.

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Related Questions

What is the parent function of absolute value?

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Which is not a characteristic of the absolute value parent function?

the range is all real numbers


What are the domain and range of the absolute value parent function?

The domain of the absolute value parent function, ( f(x) = |x| ), is all real numbers, expressed as ( (-\infty, \infty) ). The range is all non-negative real numbers, represented as ( [0, \infty) ), since the absolute value cannot be negative.


What of the following is a key property of the absolute value parent function?

It’s vertex is not at the origin


What is the range of absolute value parent function?

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Which of the following is a key property of the absolute value parent function?

Its vertex is not at the origin


What is an absolute function?

The absolute value function returns the absolute value of a number.


What is a function whose rule contains absolute value expressions?

An absolute-value function


What is the difference of x intercept and y intercept?

The y-intercept is the value of the function when 'x' is zero. That is, it's the point at which the graph of the function intercepts (crosses) the y-axis. The x-intercept is the value of 'x' that makes the value of the function zero. That is, it's the point at which 'y' is zero, and the graph of the function intercepts the x-axis.


What is the relationship between the function's equation and the y-intercept?

The y-intercept is the value of the function (if it exists) when x = 0.


If you horizontally shift the absolute value parent function F(x) x left three units what is the equation of the new function?

To horizontally shift the absolute value parent function ( F(x) = |x| ) three units to the left, you replace ( x ) with ( x + 3 ). This results in the new function ( F(x) = |x + 3| ). Thus, the equation of the shifted function is ( F(x) = |x + 3| ).


Is an absolute value function a polynomial function?

No it is not