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Yes, if angles are 45, 45 and 90.

It's called an isosceles triangle.

Okay, but what if the triangle has to equal to 60?

What's 60? The area, perimeter, what?

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Q: Is there a right triangle where sides a and b are congruent?
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Which polygon has no right angles and 3 congruent sides?

a rectangle too but in my homework page it has: A.Rhombus B.Equileteral triangle C.Parallelogram D.Scalene triangle Is it B? Yes it isno because it dose not tell you the answer


Does a right triangle have equal sides?

no. according to Pythagoras. If a, b,c are 3 sides of a right angled triangle, a2 +b2 = c2


How do you solve right triangle?

A right triangle has three sides. If you label the sides connected to the right angle side A and side B, and the hypotenuse side C, A^2+B^2=C^2.


How do you prove the isosceles triangle theorem?

The isosceles triangle theorem states: If two sides of a triangle are congruent, then the angles opposite to them are congruent Here is the proof: Draw triangle ABC with side AB congruent to side BC so the triangle is isosceles. Want to prove angle BAC is congruent to angle BCA Now draw an angle bisector of angle ABC that inersects side AC at a point P. ABP is congruent to CPB because ray BP is a bisector of angle ABC Now we know side BP is congruent to side BP. So we have side AB congruent to BC and side BP congruent to BP and the angles between them are ABP and CBP and those are congruent as well so we use SAS (side angle side) Now angle BAC and BCA are corresponding angles of congruent triangles to they are congruent and we are done! QED. Another proof: The area of a triangle is equal to 1/2*a*b*sin(C), where a and b are lengths of adjacent sides, and C is the angle between the two sides. Suppose we have a triangle ABC, where the lengths of the sides AB and AC are equal. Then the area of ABC = 1/2*AB*BC*sin(B) = 1/2*AC*CB*sin(C). Canceling, we have sin(B) = sin(C). Since the angles of a triangle sum to 180 degrees, B and C are both acute. Therefore, angle B is congruent to angle C. Altering the proof slightly gives us the converse to the above theorem, namely that if a triangle has two congruent angles, then the sides opposite to them are congruent as well.


How do you find one of the shorter sides of a right angled triangle knowing the hypotenuse and one of the shorter sides?

a^2 + b^2 = c^2 c= hypotenuse a and b are the legs (sides) of the triangle