a rectangle too but in my homework page it has: A.Rhombus B.Equileteral triangle C.Parallelogram D.Scalene triangle Is it B? Yes it isno because it dose not tell you the answer
no. according to Pythagoras. If a, b,c are 3 sides of a right angled triangle, a2 +b2 = c2
A right triangle has three sides. If you label the sides connected to the right angle side A and side B, and the hypotenuse side C, A^2+B^2=C^2.
The isosceles triangle theorem states: If two sides of a triangle are congruent, then the angles opposite to them are congruent Here is the proof: Draw triangle ABC with side AB congruent to side BC so the triangle is isosceles. Want to prove angle BAC is congruent to angle BCA Now draw an angle bisector of angle ABC that inersects side AC at a point P. ABP is congruent to CPB because ray BP is a bisector of angle ABC Now we know side BP is congruent to side BP. So we have side AB congruent to BC and side BP congruent to BP and the angles between them are ABP and CBP and those are congruent as well so we use SAS (side angle side) Now angle BAC and BCA are corresponding angles of congruent triangles to they are congruent and we are done! QED. Another proof: The area of a triangle is equal to 1/2*a*b*sin(C), where a and b are lengths of adjacent sides, and C is the angle between the two sides. Suppose we have a triangle ABC, where the lengths of the sides AB and AC are equal. Then the area of ABC = 1/2*AB*BC*sin(B) = 1/2*AC*CB*sin(C). Canceling, we have sin(B) = sin(C). Since the angles of a triangle sum to 180 degrees, B and C are both acute. Therefore, angle B is congruent to angle C. Altering the proof slightly gives us the converse to the above theorem, namely that if a triangle has two congruent angles, then the sides opposite to them are congruent as well.
a^2 + b^2 = c^2 c= hypotenuse a and b are the legs (sides) of the triangle
The isosceles triangle theorem states that if two sides of a triangle are congruent, the angles opposite of them are congruent. The converse of this theorem states that if two angles of a triangle are congruent, the sides that are opposite of them are congruent.
a rectangle too but in my homework page it has: A.Rhombus B.Equileteral triangle C.Parallelogram D.Scalene triangle Is it B? Yes it isno because it dose not tell you the answer
no. according to Pythagoras. If a, b,c are 3 sides of a right angled triangle, a2 +b2 = c2
For any triangle, it is the sum of the lengths of the sides a, b, and c. (P = a + b + c)For a right triangle, it is a + b + [sq rt (a2 + b2)]for the two sides and the hypotenuse (diagonal).It is the sum of its 3 sides
A right triangle has three sides. If you label the sides connected to the right angle side A and side B, and the hypotenuse side C, A^2+B^2=C^2.
The isosceles triangle theorem states: If two sides of a triangle are congruent, then the angles opposite to them are congruent Here is the proof: Draw triangle ABC with side AB congruent to side BC so the triangle is isosceles. Want to prove angle BAC is congruent to angle BCA Now draw an angle bisector of angle ABC that inersects side AC at a point P. ABP is congruent to CPB because ray BP is a bisector of angle ABC Now we know side BP is congruent to side BP. So we have side AB congruent to BC and side BP congruent to BP and the angles between them are ABP and CBP and those are congruent as well so we use SAS (side angle side) Now angle BAC and BCA are corresponding angles of congruent triangles to they are congruent and we are done! QED. Another proof: The area of a triangle is equal to 1/2*a*b*sin(C), where a and b are lengths of adjacent sides, and C is the angle between the two sides. Suppose we have a triangle ABC, where the lengths of the sides AB and AC are equal. Then the area of ABC = 1/2*AB*BC*sin(B) = 1/2*AC*CB*sin(C). Canceling, we have sin(B) = sin(C). Since the angles of a triangle sum to 180 degrees, B and C are both acute. Therefore, angle B is congruent to angle C. Altering the proof slightly gives us the converse to the above theorem, namely that if a triangle has two congruent angles, then the sides opposite to them are congruent as well.
According to the Pythagorean theorem, the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides or, c^2 = a^2 + b^2. Since there is no single value where a = b= c, a right triangle cannot have all equal sides.
If the lengths of the sides of the triangle can be substituted for 'a', 'b', and 'c'in the equationa2 + b2 = c2and maintain the equality, then the lengths of the sides are a Pythagorean triple, and the triangle is a right one.
a^2 + b^2 = c^2 c= hypotenuse a and b are the legs (sides) of the triangle
Let the sides be a & b. a2 + b2 = The square of the hypotenuse a/b = tangent of the angle opposite a b/a = tangent of the angle opposite b ab/2 = the area of a right angled triangle.
isosceles has 2 congruent angles 2 congruent sides right triangles has sides that consist of 2 legs and a hypotenuse. in the Pythagorean therom. a+b are legs...A2 +B2=C2 one right angle(90)
the length of the sides of a right triangle with sides A and B and a hypotenuse C: A2 +B2 = C2