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No. If a,b,c are the legs of (any) triangle, then by the triangle inequality,

a + b > c

This is because the shortest distance between two fixed points is a straight line. If c is the hypotenuse, then the sum of the two legs must be strictly greater than c. However, for a right triangle, the sum of the *squares* of the two legs must be equal to the length of the *square* of the third side. For example, 3-4-5 is a right triangle, because 32 + 42 = 52.

Q: Is there ever a case when hypotenuse is equal to leg one plus leg two?

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The side opposite the right triangle is the hypotenuse. The formula for finding the hypotenuse is A squared plus B squared equal C squared. C is the hypotenuse. If side A is 3 and side B is 4, the equation would read 9 plus 16 equal C squared, or 25 equals C squared. The square of 25 is 5, so the hypotenuse is 5.

The perimeter is equal to the sum of (leg-1) plus (leg-2) plus (hypotenuse).

In a right angle triangle the base squared (a) plus the height squared (b) is equal to the hypotenuse squared (c) Pythagoras' theorem: a2+b2 = c2

In a right angle triangle the square of the hypotenuse is equal to height squared plus base squared

That a right angle triangle's base when squared plus its height when squared is equal to its hypotenuse when squared:- a2+b2 = c2

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The side opposite the right triangle is the hypotenuse. The formula for finding the hypotenuse is A squared plus B squared equal C squared. C is the hypotenuse. If side A is 3 and side B is 4, the equation would read 9 plus 16 equal C squared, or 25 equals C squared. The square of 25 is 5, so the hypotenuse is 5.

The perimeter is equal to the sum of (leg-1) plus (leg-2) plus (hypotenuse).

In a right angle triangle the base squared (a) plus the height squared (b) is equal to the hypotenuse squared (c) Pythagoras' theorem: a2+b2 = c2

In a right angle triangle the square of the hypotenuse is equal to height squared plus base squared

The hypotenuse of a right angle triangle when squared is equal to the base squared plus the height squared and the formula is usually given as:- a2+b2 = c2 whereas a and b are the base and height respectively and c being the hypotenuse which is the largest side

One particular triangle with sides measuring 3, 4 and 5 units is a right angled triangle. Such a triangle meets with Pythagoras's Theorem "The square on the hypotenuse is equal to the sum of the squares on the other two sides." In this case, the hypotenuse measures 5 units. Then, 52 = 32 + 42 25 = 9 + 16 = 25

You mean a isoceles? An isoceles wouldn't have a right angle but would have 2 equal sides and 1 unequal in which case the values are x and x(root)2, In a right triangle the values are x , 2x , and x(root)3. The short side is x, and the long leg is 2x and the hypotenuse is x(root)3. If you are looking for the hypotenuse equation it is a(squared) + b(squared) = c(squared) in other words, leg one squared plus leg two squared equals hypotenuse squared.

That a right angle triangle's base when squared plus its height when squared is equal to its hypotenuse when squared:- a2+b2 = c2

That for any right angle triangle the length of its hypotenuse when squared is equal to the of length of the base when squared plus the length of the height when squared:- a2+b2 = c2 where a and b are the base and the height of the triangle and c is its hypotenuse.

It's the longest side. If a and b are the shorter sides, the square root of a squared plus b squared will equal the length of the hypotenuse

The square of the length of the base plus the square of the length of the height will equal the square of the length of the hypotenuse of your right triangle, per Pythagoras. Square the hypotenuse, subtract the square of the height, and then find the positive square root of that and you'll have the base of your right triangle.

no, never