(a+b)(a+b)Also equal to a2+2ab+b2
(a+b)2
4
Pythagoras.
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
A^2 + B^2 = C^2 Side A squared plus Side B squared has to equal Side C squared
(a+b)(a+b)Also equal to a2+2ab+b2
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
Because it is mathematically incorrect. a^2 + b^2 = c^2 Take square root of both sides. SQRT (a^2 + b^2) = c So you see, it is not a plus b equal c.
It is the formula for Pythagoras' theorem for right angle triangles.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
It is: 2b squared
It's the longest side. If a and b are the shorter sides, the square root of a squared plus b squared will equal the length of the hypotenuse
It's equal to positive b squared, or (b x b) .
(a + 2 - b) (a + 2 + b)
The formula for finding the angles is called " Pythagorean Thyrum " It states that a squred plus b squared equals c squared so therefore c squared minus a squared will equal b squared. i hope that helps