No, the acute angle is LESS than 45 degrees.Improved Answer:-Yes it can be because an acute angle is any angle greater than 0 but less than 90 degrees
No. For temperatures, 45°C is much hotter than 45°F (equal to 7.22°C). Likewise, a change in temperature of 45 "degrees" on the Celsius scale is a much larger change than 45 "degrees" on the Fahrenheit scale. The Fahrenheit "degrees" are smaller intervals. Technically the numbers have the same value, but on different scales.
It is an acute angle because it is greater than 0 but less than 90 degrees.
45 is greater than 37
The least prime number that is greater than 45 is 47.
No because 45 degrees is an acute angle that is greater than 0 but less than 90 degrees.
1 cot(theta)=cos(theta)/sin(theta) cos(45 degrees)=sqrt(2)/2 AND sin(45 degrees)=sqrt(2)/2 cot(45 deg)=cos(45 deg)/sin(deg)=(sqrt(2)/2)/(sqrt(2)/2)=1
No, the acute angle is LESS than 45 degrees.Improved Answer:-Yes it can be because an acute angle is any angle greater than 0 but less than 90 degrees
Let m be the slope in percent and theta be the angle in question. tan (theta) = m/100 theta = arctan (m/100) To verify the result, we know the following: tan 0 = 0 tan (45 degrees) = 1 = 100% tan (90 degrees) = infinity For example, if 0 < m < 100%, then 0 < theta < 45 degrees.
No. For temperatures, 45°C is much hotter than 45°F (equal to 7.22°C). Likewise, a change in temperature of 45 "degrees" on the Celsius scale is a much larger change than 45 "degrees" on the Fahrenheit scale. The Fahrenheit "degrees" are smaller intervals. Technically the numbers have the same value, but on different scales.
No because .5 is greater than .45
It is an acute angle because it is greater than 0 but less than 90 degrees.
The mechanical advantage of an inclined plane is the ratio of its length to the height of its lift. At 45 degrees, this ratio is equal to one. Less than 45 degrees and it is greater than one, more than 45 degrees, and it it less than one. So the answer is yes.
It is an acute angle because it is greater than 0 but less than 90 degrees.
When a projectile is shot at ground level the range formula is this... d = (v2/g) * sin 2*theta d=range v=velocity g=speed of gravity sin= sine function theta=angle that you make when the projectile is shot In your question you are asking about theta. The maximum distance you will get is when theta is 45 degrees. This is because of gravity. Gravity is pulling down on the object. When something is shot above 45 degrees gravity pull down on the object the same way as it pulls down on the corresponding angle below 45 degrees. When I say corresponding angle look below. Basically the answer to your question is because of gravity. Corresponding angles... 44 and 46 50 and 40 10 and 80 15 and 75 89 and 1 30 and 60 90 and 0 If you notice they all add up to 90 degrees. 90 degrees is the highest angle that can be shot. If it is greater than 90 degrees then the projectile will go behind you.
You must think of the unit circle. negative theta is in either radians or degrees and represents a specific area on the unit circle. Remember the unit circle is also like a coordinate plane and cos is the x while sin is the y coordinate. Here is an example: cos(-45): The cos of negative 45 degrees is pi/4 and cos(45) is also pi/4
45 is greater than 0.43; 0.45 is also greater than 0.43