sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o
sin theta = opp/hyp sin 45 = opp/1 opp = sin 45 = sqrt(2)/2 ~= 0.7071
The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))
One relationship is: cos(x) = sin(90° - x) if you use degrees. Or in radians: cos(x) = sin(pi/2 - x) Another relationship is the pythagorean identity.
For such simplifications, it is usually convenient to convert any trigonometric function that is not sine or cosine, into sine or cosine. In this case, you have: sin theta / sec theta = sin theta / (1/cos theta) = sin theta cos theta.
1 cot(theta)=cos(theta)/sin(theta) cos(45 degrees)=sqrt(2)/2 AND sin(45 degrees)=sqrt(2)/2 cot(45 deg)=cos(45 deg)/sin(deg)=(sqrt(2)/2)/(sqrt(2)/2)=1
Sin theta of 30 degrees is1/2
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
answer is 2.34 degrees answer is 2.34 degrees
Sin(theta) = 0.03125 Hence theta = ArcSin(0.03125) theta = 1.790784659... degrees.
sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o
108.435 degrees 288.435 degrees (decimal is rounded)
sin theta = opp/hyp sin 45 = opp/1 opp = sin 45 = sqrt(2)/2 ~= 0.7071
if x if ArcSine 1.5 degrees means the sin(x)=1.5 but the range of the sin(theta) for all angles theta is between o and 1 inclusive. So there is no real answer.
You must think of the unit circle. negative theta is in either radians or degrees and represents a specific area on the unit circle. Remember the unit circle is also like a coordinate plane and cos is the x while sin is the y coordinate. Here is an example: cos(-45): The cos of negative 45 degrees is pi/4 and cos(45) is also pi/4
COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.