It could be but more details are required.
To determine an ordered pair that could be a solution to an inequality, you need to substitute the values of the ordered pair into the inequality and check if it satisfies the condition. For example, if the inequality is (y < 2x + 3) and the ordered pair is (1, 4), you would substitute (x = 1) and (y = 4) to see if (4 < 2(1) + 3) holds true. If it does, then (1, 4) is a solution; if not, you would need to try another pair.
To determine if an ordered pair ((x, y)) is a solution to the inequality (3y - 1 - 2x \geq 0), we can rearrange it to (3y \geq 2x + 1). For example, if we take the ordered pair ((1, 1)), we substitute (x = 1) and (y = 1): (3(1) \geq 2(1) + 1), which simplifies to (3 \geq 3). Since this is true, ((1, 1)) is a valid solution to the inequality.
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
The solution to an inequality generally is a region with one more dimension. If the inequality/equation is of the form x < a or x = a then the solution to the inequality is the 1 dimensional line segment while the solution to the equality is a point which has no dimensions. If the inequality/equation is in 2 dimensions, the solution to the inequality is an area whereas the solution to the equality is a 1-d line or curve. And so on, in higher dimensional spaces.
To determine if 2 is a solution to the inequality (x), we need to clarify the specific inequality being referenced. If we're considering a simple inequality such as (x > 1), then 2 is indeed a solution because it satisfies the condition. However, if the inequality is (x < 1), then 2 would not be a solution. Please provide the complete inequality for an accurate assessment.
To determine an ordered pair that could be a solution to an inequality, you need to substitute the values of the ordered pair into the inequality and check if it satisfies the condition. For example, if the inequality is (y < 2x + 3) and the ordered pair is (1, 4), you would substitute (x = 1) and (y = 4) to see if (4 < 2(1) + 3) holds true. If it does, then (1, 4) is a solution; if not, you would need to try another pair.
To determine if an ordered pair ((x, y)) is a solution to the inequality (3y - 1 - 2x \geq 0), we can rearrange it to (3y \geq 2x + 1). For example, if we take the ordered pair ((1, 1)), we substitute (x = 1) and (y = 1): (3(1) \geq 2(1) + 1), which simplifies to (3 \geq 3). Since this is true, ((1, 1)) is a valid solution to the inequality.
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
Substitute the values of the ordered pair into the relation. If the equation is valid then the ordered pair is a solution, and if not then it is not.
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
1/8
1
The solution to an inequality generally is a region with one more dimension. If the inequality/equation is of the form x < a or x = a then the solution to the inequality is the 1 dimensional line segment while the solution to the equality is a point which has no dimensions. If the inequality/equation is in 2 dimensions, the solution to the inequality is an area whereas the solution to the equality is a 1-d line or curve. And so on, in higher dimensional spaces.
y=(-1) x=(2)
To determine if 2 is a solution to the inequality (x), we need to clarify the specific inequality being referenced. If we're considering a simple inequality such as (x > 1), then 2 is indeed a solution because it satisfies the condition. However, if the inequality is (x < 1), then 2 would not be a solution. Please provide the complete inequality for an accurate assessment.
-4y=x is the equation of a line and has infinite solutions. Each solution is an ordered pair. We usually write this as (x,y). It is called an ordered pair because we cannot exchange the x and y in general. So (x,y) does not generally equal (y,x).Now in this case, pick any value for x, say 0, and y is 0. The solution (0,0) is one ordered pair.Now, take x=1 and y=-1/4. So (1, -1/4) is another solution.
Although no incomplete ordered pairs have been shown they can be readily solved.If x + y - 1 = 0, then x = 1 - y, also y = 1 - x.From the above formulae for x and y then any omissions can be completed.EXAMPLE : complete the ordered pairs (1) (7, y) and (2) (x, -4)(1) y = 1 - x = 1 - 7 = -6 : The ordered pair is thus (7, -6)(2) x = 1 - y = 1 -(-4) = 5 : The ordered pair is thus (5, -4)