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w2-3w = 0 w(w-3) = 0 w = 3 or w = 0
start real length L and width w calculate the area A= Lw calculate the circumference C=2(L+w) Display A and C End
Means that the clock is supposed to be able to be submerged to a depth of 30 meters w/o taking in water.
The shorter side, W, can be any one of the infinite number of real values less than sqrt(120) = 10.9545 cm. The longer side must be 120/W cm.
Designate the length and width in meters by l and w respectively. Then, ,from the problem statement, l = 6 + 2w and l X w = 140. Substituting the first of these equations into the second yields w(6 + 2w) = 140, or, rearranging into standard form, 2w2 + 6w - 140 = 0; dividing by 2 gives w2 + 3 w - 70 = 0. This can be factored into (w-7)(w+10) = 0, which is true for either w = -10 or w = 7. A real rectangle, however, can not have a negative width; therefore, w = 7 and l = 20.