w=width
It can represent formulas like A=L×W etc...
P = 2 (L + W) and A = L x W
21% Area = length*width Let Aoriginal represent the original area and Aheated represent the area of the rectangle after heating. Let l and w represent the original length and width of the rectangle. Because l and w increase by 10% on heating, we have the following: Aheated = (1.10*l)(1.1*w)=1.21(l*w) Because Aoriginal = l*w, Aheated =1.21(l*w)=1.21*Aoriginal So the area of the rectangle increases by 21% upon heating.
P=(L+W)x2 Where P = Perimeter, L=Length and W=Width.
Represent the length of the rectangle by L and the width by W. The perimeter = 2L + 2W = 2(L + W). The area = L x W.
w=width
As a term of an expression in math, 72w means 7 times w
A=l*w
To write one tenth of w in an algebraic expression, you can use the expression (1/10)w or w/10. Both of these expressions represent dividing w by 10, which is equivalent to finding one tenth of w.
It can represent formulas like A=L×W etc...
P = 2 (L + W) and A = L x W
21% Area = length*width Let Aoriginal represent the original area and Aheated represent the area of the rectangle after heating. Let l and w represent the original length and width of the rectangle. Because l and w increase by 10% on heating, we have the following: Aheated = (1.10*l)(1.1*w)=1.21(l*w) Because Aoriginal = l*w, Aheated =1.21(l*w)=1.21*Aoriginal So the area of the rectangle increases by 21% upon heating.
P=(L+W)x2 Where P = Perimeter, L=Length and W=Width.
L x W
You can use the distributive property to factor the expression (2l + 2w). By factoring out the common factor of 2, you can rewrite the expression as (2(l + w)). This shows that the sum of (2l) and (2w) can be expressed as twice the sum of (l) and (w).
it cannot be solved------------------------------------------------Actually, you can. Suppose, as an example, that the rectangle's area and perimeter are 6 and 10 respectively. Let therectangles length and width be represented by L and W respectively. ThenLW = 6 (a) and2 ( L + W ) = 10 (b)Let me rearrange (b) to obtain an expression for W: W = 5 - L.Now let me substitute this expression for W in (a): L ( 5 - L ) = 6.This is a quadratic equation that one can solve for L. Let me do it by factoring,L^2 - 5 L + 6 = 0 = ( L - 2 ) ( L - 3 )This implies that L=2 or L=3. With L=2, W=3; with L=3, W=2. Put simply the rectangle's length and width are 3 and 2 respectively.