Y = X2 Is a parabolic function.
no, but y = x2 is a function
No, because there is more than one solution: y2 = x2 y = ±(x2)1/2 y = ±x Because there are multiple solutions for a single value of x, this does not qualify as a function.
No. A simple example of this is y = x2; the inverse is x = y2, which is not a function.
Implicit: x2 + 2y = 5 Explicit : y = (5 - x2)/2
If you mean: x^2 + y^2 = 121 then the radius is the square root of 121 which is 11
the function (x),sory I can`t use the sign of the function because it is not available. the function of (x)=4x+4 is one to one function assume function(x1)= function(x2) then 4(x1)+4 =4(x2)+4 4(x1)=4(x2) (x1)=(x2) hence,the function is one to one
No. x2+5x is a polynomial, an algebraic expression or a formula, but it is not a function. It could be used to help define a function. {(x,y) | y = x2 + 5x , x any real number} is a function
Y = X2 Is a parabolic function.
X2 9 can be described mathematically to be a quadratic function.
x2
Yes. Think of y as being a function of x. y = f(x) = x2 + 1
no, but y = x2 is a function
No, because there is more than one solution: y2 = x2 y = ±(x2)1/2 y = ±x Because there are multiple solutions for a single value of x, this does not qualify as a function.
To evaluate a function means to replace the variable with some value, and calculate the value of the function. For example, in the parabola y = x2 (or, using functional notation, f(x) = x2), if you replace x with 10, and calculate x2, you are evaluating the function for that specific value.
No. A simple example of this is y = x2; the inverse is x = y2, which is not a function.
Need two points. m = slope. (X1, Y1) and (X2, Y2) m = Y2 - Y1/X2 - X1 ==============Or, if function is in this form...... Y =mX + b ======== Read off of function, or get function is this form.