If: x2 = 81 Then: x = 9 or x = -9
x2+2x-63 = (x-7)(x+9) when factored
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).
x2 + 8x - 9 factors to (x - 1)(x + 9) x2 - 1 factors to (x - 1)(x + 1) The LCM will be (x - 1)(x + 1)(x + 9) or x3 + 9x2 - x - 9 The GCF is (x - 1)
I hope you mean x3+2x2-9x+18. Treat the equation like two equations: x3+2x2 and 9x+18. Factor out x2 from the first equation, so x2(x+2). Factor out 9 from the second equation, so 9(x+2). Now, the whole equation. x2(x+2)-9(x+2). Factor out (x+2), so (x+2)(x2-9). (x2-9) factors into (x+3)(x-3). So, (x+2)(x+3)(x-3) is the complete factorization. Hope this helps.
-7
x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.
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d/dx (x2+ 9)1/2= 1/2*(x2+ 9)-1/22x = x(x2+ 9)-1/2or x/(x2+ 9)1/2
If: x2 = 81 Then: x = 9 or x = -9
9 - x2 will factor into (3 - x)(3 + x)
x2+24x+144 = 9 x2+24x+144-9 = 0 x2+24x+135 = 0 (x+9)(x+15) = 0 x = -9 or x = -15
First, it is important to regroup, so I am going to rearrange this equation: (x4 - 7x2 - 18 - 3x3 + 27x I can now factor the first three terms and the last two terms: (x4 - 7x2 - 18) becomes (x2 - 9)(x2 + 2) -3x3 + 27x becomes -3x(x2 - 9); so the new equation looks like: (x2 - 9)(x2 + 2) - 3x(x2 - 9) From here, factor out what is common, in this case- x2- 9. Therefore, you will have (x2 - 9)(x2 + 2 - 3x), which can be rearranged to (x2 -9)(x2 - 3x + 2). Further factoring reveals (x + 3)(x - 3)(x - 1)(x - 2) as the final answer.
x2-9x = x(x-9)
x2+2x-63 = (x-7)(x+9) when factored
The GCF is x2.