If you are speaking of an entity which has a graph on the xy plane that is of the form
y = f(x)
then it IS NOT a function.
An equation which defines a relation on the xy plane is the equation of a
function, if and only if it has a graph that is not crossed more than once by
a vertical line. However the graph of x=2 is indeed a vertical line in the xy
plane consequently IT IS NOT A FUNCTION.
In most algebra and precalculus courses, the concept of function is assumed
to refer to a function y=f(x). However if we were to think in the reverse direction
where y was an independent variable and x were the dependent variable, then
we could assert that it is a function x=f(y) = 2 which is now a constant.
For most basic courses in mathematics however, your answer is NO, it is not a function.
Yes, y=-2+x is a linear function.
Y=X^2 is a function for it forms a parabola on a graph.
2x-2/x^2+3x-4
X - Y^2 = 1 - Y^2 = - X + 1 Y^2 = X - 1 Y = (+/-) sqrt(X - 1) now, X is represented as a function of Y. Function values are generally Y values.
3
Yes, y=-2+x is a linear function.
It is 1.2164
False. It is true for a function that is continuous at x=2, but it is not generally true for all functions. For a counterexample, consider the function f(x), such that: f(x)=x for x not equal to 2 f(x)=0 for x=2 The limit of this function as x approaches 2 is 2 (since we can make f(x) as close to 2 as we want as x gets closer to 2), but f(2) does not equal the limit of f(x) as x approaches 2.
f(x) = 2*(x-3)*(x+2)/(x-1) for x ≠1
y = -x-2
No.
The "root" of a function is also called the "zero" of a function. This is where the function equals zero. The function y=4-x2 has roots at x=2 and x=-2 The function y=4-x2 has zeroes at x=2 and x=-2 Those are equivalent statements.
x + y = -2 y = -x - 2 f(x)= - x -2
Y=X^2 is a function for it forms a parabola on a graph.
2 pi
2x-2/x^2+3x-4
y = 8 - 2*x