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y = x / (x^2 + 2x + 1) The horizontal asymptote is y = 0
y = 1. When the degree of your numerator is the same with the degree of your denominator, then y = the ratio of the leading coefficients of the numerator and denominator is the horizontal asymptote.
2x-2/x^2+3x-4
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The graph of an exponential function f(x) = bx approaches, but does not cross the x-axis. The x-axis is a horizontal asymptote.
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y = x / (x^2 + 2x + 1) The horizontal asymptote is y = 0
The horizontal asymptote is what happens when x really large. To start with get rid of all the variables except the ones with the biggest exponents. When x is really large, they are the only ones that will matter. If the remaining exponents are the same, then the ratio of those coefficients tell you where the horizontal asymptote is. For example if you have 2x3/3x3, then the ratio is 2/3 and the asymptote is f(x)=2/3 or y=2/3. If the exponent in the denominator is bigger, than y=0 is the horizontal asymptote. If the exponent in the numerator is bigger, than there is no horizontal asymptote.
Yes.
It is y = 0
y = 1. When the degree of your numerator is the same with the degree of your denominator, then y = the ratio of the leading coefficients of the numerator and denominator is the horizontal asymptote.
2x-2/x^2+3x-4
Nope not all the rational functions have a horizontal asymptote
To Find Horizontal Asymptotes: 1) Put equation or function in standard form. 2) Remove everything except the biggest exponents of x found in the numerator and denominator. then set this number to y= and this is the horizontal asymptote Here is an example: f(x) = (2x^2 + 5x - 3)/(x^2 - 2x) We get rid of everything except the biggest exponents of x found in the numerator and denominator. After we do that, the above function becomes: f(x) = 2x^2/x^2. Cancel x^2 in the numerator and denominator and we are left with 2. The horizontal asymptote for is the horizontal line y=2.
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