In mathematics, the variable "y" and "1y" are equivalent because "1" is the multiplicative identity, meaning any number multiplied by 1 remains unchanged. Therefore, "1y" is equivalent to just "y" as they represent the same value. This property is fundamental in algebraic manipulations and simplifications.
Well, honey, technically speaking, "y" and "1y" are not equivalent because the "1" in front of the "y" implies multiplication. So, "y" is just "y," while "1y" means you're multiplying 1 by y, which is still just y. It's like saying you have one apple and one apple - you're still left with just one apple at the end of the day.
Oh, dude, you're hitting me with some math lingo now? Alright, so technically speaking, y and 1y are equivalent because 1 times any number is just that number. It's like saying you have one slice of Pizza versus just saying you have a slice of pizza. Same thing, just different ways of saying it.
y-2y8y-6 1y-2y8y-6 1y-6y-6 5y-6 1y
When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
The algebraic expression of: -x-1y has the same value as -x-y
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
y = 2x + 1 1. Make a table: x = -2; y = -3y = 2x + 1y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1y = 2x + 1y = 2(-1) + 1 = -2 + 1 = -1x = 0; y = 1y = 2x + 1y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3y = 2x + 1y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5y = 2x + 1y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1
y-2y8y-6 1y-2y8y-6 1y-6y-6 5y-6 1y
Pls, answer thank you :)
When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
Y=2xx+y=3x+(2x)=33x=3x=1y=2x y=2*1y=2
The algebraic expression of: -x-1y has the same value as -x-y
6-1y+(5y-6y) = 6-y+(-1y) = 6
-2y+y = -y
4x + 3y = 1y = 2x + 8 Take the first part: 4x + 3y = 1y 4x = 1y - 3y 4x = -2y x = -y/2 Substitute x in second part: 1y = 2x + 8 1y = -2y/2 + 8 1y = -1y + 8 2y = 8 y = 4 Substitute y into either part: 1y = 2x + 8 1(4) = 2x + 8 4 - 8 = 2x -4 = 2x x = -2 Therefore: x = -2 y = 4
6x -1y = 9 y-intercept = -9
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
1
y = 2x + 1 1. Make a table: x = -2; y = -3y = 2x + 1y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1y = 2x + 1y = 2(-1) + 1 = -2 + 1 = -1x = 0; y = 1y = 2x + 1y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3y = 2x + 1y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5y = 2x + 1y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1