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I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3
X + 3y - 2y + 3y = X + (3-2+3)y = X + 4y
3x + 7y
3y+1
If y + 3y + 10 = 70, then 4y + 10 = 70, and 4y = 60. We then find that y = 60/4 = 15.