answersLogoWhite

0

It depends on what z and x are. Since you did not share that information, it is not possible to give a sensible answer.

User Avatar

Wiki User

12y ago

Still curious? Ask our experts.

Chat with our AI personalities

CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra

Add your answer:

Earn +20 pts
Q: Is z a subset of x?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Math & Arithmetic

What is x-y-z plane?

It is a particular 2-dimensional subset of 3-dimensional space.


Is x subset of f?

It depends on what x and f are.


Is RR subset of complex number C?

If a complex number z = (x, y) = x +iy where x and y are real numbers (and i is the imaginary root of -1), then RxR is is isomorphic to C. This means that the two sets are equivalent.


What is meant by a subgroup generated by an element x belongs to group G?

It is a subset of the Group G which has all the properties of a Group, namely that it is a set of elements (numbers) with a binary operation (addition) that combines any two elements in the set to form a third element which is also in the set. The Group satisfies four axioms: closure, associativity, identity and invertibility. The set of integers, Z, is a Group, with addition as the binary operation. [It is also a Ring, but that is not important here]. The set of all multiples of 7 is a subgroup of Z. Denote the subgroup by Z7. It is a Group because: Closure: If x and y are in Z7, then x = 7*p for some p in Z and y = 7*q for some q in Z. Then x + y = 7*p + 7*q = 7*(p+q) where p+q is in Z because Z is a Group. Therefore 7*(p+q) is in Z7. Associativity: If x (= 7p), y (= 7q) and z (= 7r) are in 7Z, then (x + y) + z = (7p + 7q) + 7r since these are in Z an Z is associative, = 7p + (7q + 7r) = x + (y + z). Identity: The additive identity is 0, since 0 + x = 0 + 7p = 7p since 0 is the additive identity in Z. Invertibility: If x = 7a is in Z7 then 7*(-a) is also in 7Z. If 7*(-a) is denoted by -x, then x + (-x) = 7a + 7*(-a) = 0 and so -x is the additive inverse of x. But there are elements of Z, for example, 2 which are not in Z7 so Z7 it is a proper subset of Z.


What is the proper subset?

The set X is a proper subset of Y if Xcontains none or more elements from Y and there is at least one element of Y that is not in X.