This problem can be modeled and tested quite easily. Set A can be [X,Y], subset B [X,Y], and subset A [X,Y]. Therefore A and B are equivalent.
If all elements of set A are also elements of set B, then set A is a subset of set B.
An improper subset is identical to the set of which it is a subset. For example: Set A: {1, 2, 3, 4, 5} Set B: {1, 2, 3, 4, 5} Set B is an improper subset of Set Aand vice versa.
Since B is a subset of A, all elements of B are in A.If the elements of B are deleted, then B is an empty set, and also it is a subset of A, moreover B is a proper subset of A.
For example, if we have a set of numbers called A which has 3 members(in our case numbers): A={2,5,6} this set has 8 subsets (2^3) which are as follow: the empty set: ∅ {2},{5},{6} {2,5},{2,6},{5,6} {2,5,6}
Suppose A is a subset of S. Then the complement of subset A in S consists of all elements of S that are not in A. The intersection of two sets A and B consists of all elements that are in A as well as in B.
If you want to show that A is a subset of B, you need to show that every element of A belongs to B. In other words, show that every object of A is also an object of B.
A set "A" is said to be a subset of of set "B", if every element in set "A" is also an element of set "B". If "A" is a subset of "B" and the sets are not equal, "A" is said to be a proper subset of "B". For example: the set of natural numbers is a subset of itself. The set of square numbers is a subset (and also a proper subset) of the set of natural numbers.
If set A and set B are two sets then A is a subset of B whose all members are also in set B.
A set A is a subset of a set B if A is "contained" inside B.
Set "A" is said to be a subset of set "B" if it fulfills the following two conditions:A is a subset of B, andA is not equal to B
A is a subset of a set B if every element of A is also an element of B.
Assume that set A is a subset of set B. If sets A and B are equal (they contain the same elements), then A is NOT a proper subset of B, otherwise, it is.
If all the elements in set A are also elements of set B, then set A is a subset of set B.
A proper subset B of a set A is a set all of whose elements are elements of A nad there are elements of A that are not elements of B. It follows, then, that an improper subset must be the whole set, A. That is, A is an improper subset of A
If all elements in set "A" are also elements of set "B", then set "A" is a subset of set "B". If the sets are not equal (set "B" also has some elements that are not in set "A"), then set "A" is a PROPER subset of set "B".Answer:In simple words: a subset is a set (a group) that is within another set. For example, the set of odd integers (odd numbers) is a subset of the set of all integers.A non-math example: the set of urbanites is a subset of the set of all people.See the first Answer (above) for more detail.
empty set
An improper subset is identical to the set of which it is a subset. For example: Set A: {1, 2, 3, 4, 5} Set B: {1, 2, 3, 4, 5} Set B is an improper subset of Set Aand vice versa.