Yankeepride
Using the formula s = ut + 1/2at2, where s is the distance travelled, u is the initial velocity, a is the acceleration and t is the time , then :-
s = 0 + [1/2 x 9.8 x (9.36)2] = 429.29 meters (2dp)
The cliff is 429.29 meters high.
Wiki User
∙ 14y ago-- Acceleration of gravity, on or near Earth, is 9.8 meters ( 32.2 feet) per second2.-- Speed, neglecting the effects of air resistance, is9.8 meters (32.2 feet) per secondmultiplied by(number of seconds since the object was dropped)regardless of the mass, weight, or size of the object.
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
49
49
Ignoring air resistance . . .H = 1/2 G t2t = sqrt(2H/G) = sqrt(2 x 363 / 32.2) = 4.75 seconds (rounded)
The distance a rubber ball falls in 10 seconds will depend on the height from which it is dropped and the acceleration due to gravity. On Earth, neglecting air resistance, the general equation to calculate the distance fallen is: distance = 0.5 * acceleration due to gravity * time^2.
The ball would take approximately 4 seconds to hit the ground, neglecting air resistance. This calculation is based on the constant acceleration due to gravity (9.8 m/s²), assuming the ball is dropped and not thrown.
Surely you're aware that a falling object accelerates under the influence of gravity. That acceleration manifests itself in the form of steadily-increasing speed, so the time required to fall 186 feet depends on how long it has already been falling. -- Immediately after it's dropped, the object falls the first 186 feet in 3.399 seconds. -- It falls the NEXT 186 feet in 1.408 seconds. -- It falls the next 186 feet in 1.08 seconds. -- It falls the next 186 feet in 0.911 second. -- It falls the next 186 feet in 0.802 second. . . etc.
The speed of the rock after falling for 5 seconds would be approximately 49 m/s, neglecting air resistance. This speed is the result of the acceleration due to gravity, which is approximately 9.81 m/s^2.
The speed of an object dropped off a cliff after 5 seconds, neglecting air resistance, is given by the equation: v = gt, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time it has been falling. Plugging in the values gives v = 9.8 m/s^2 * 5 s = 49 m/s. So, the speed of the object after 5 seconds will be 49 m/s.
Assuming no air resistance, the velocity of the ball after 3 seconds can be calculated using the equation v = u + gt, where v is the final velocity, u is the initial velocity (0 m/s in this case), g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time (3 seconds). Therefore, the velocity of the ball after 3 seconds would be 29.4 m/s downward.
-- Acceleration of gravity, on or near Earth, is 9.8 meters ( 32.2 feet) per second2.-- Speed, neglecting the effects of air resistance, is9.8 meters (32.2 feet) per secondmultiplied by(number of seconds since the object was dropped)regardless of the mass, weight, or size of the object.
The acceleration of the stone when it is dropped from the top of a tower is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2 downward. This acceleration remains constant as the stone falls towards the ground, neglecting air resistance.
The velocity of the quarter after 10 seconds will be approximately 98 m/s. This value is reached when the quarter reaches its terminal velocity due to air resistance, assuming the quarter is dropped in a vacuum.
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
49
Ignoring air resistance, it's [ 9.8 meters per second2 ].Same as it was as soon as it was dropped, and same as it will be after another 42 seconds.Acceleration of gravity is constant . . . [ 9.8 meters per second2 ] until the cows come home, and even after.