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Q: If a rock is dropped off a cliff with an initial speed of 0 meters per second what is the rocks speed after 5 seconds in meters per second if it encounters no air resistance?
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Suppose a rock is dropped off a cliff with an initial speed of 0 What is the rock's speed after 5 seconds in if it encounters no air resistance?

49


Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?

29.4


Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 5 seconds in ms if it encounters no air resistance?

49


Suppose a rock is dropped off a cliff with an initial speed of 0 m per sec What is the rocks speed after 5 seconds in m per sec if it encounters no air resistance?

9.8m/s(5)= 49


Suppose a rock is dropped off a cliff with an initial speed of 0 miles per second What is the rock's speed after 5 seconds in miles per second if it encounters no air resistance?

,033


If a Rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?

speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s


Suppose a rock is dropped off a cliff with an initial speed of 0ms. what is the rocks speed after 5 second in ms if it encounters no air resistance?

The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.


Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rocks speed after 3 seconds in ms if it encounters no air resistance?

The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s


Suppose a rock is dropped off a cliff with an initial speed of 0 ms. What is the rock's speed after 5 seconds in ms if it encounters no air resistance?

The rock's speed after 5 seconds would be approximately 49 m/s. This is calculated using the formula v = g * t, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time elapsed (5 seconds).


Suppose a rock is dropped off a cliff with an initial speed of 0 ms. What is the rocks speed after 5 seconds in ms if it encounters no air resistance?

The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.


What is the rocks speed after 3 seconds in m s if it encounters no air resistance?

The rock's speed after 3 seconds, with no air resistance, can be calculated using the equation: speed = initial velocity + acceleration × time. If the rock is in free fall near the surface of the Earth, the acceleration due to gravity is approximately 9.81 m/s^2. If the rock was dropped from rest, its initial velocity would be 0 m/s. Plugging in the values, the rock's speed after 3 seconds would be 29.43 m/s.


Suppose a rock is dropped off a cliff with an initial speed of 0 miles per second What is the rocks speed after 3 seconds in miles per second if it encounters no air resistance?

The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)