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I am concerned that this question [ J plus 16-148 plus 4? ] was typed wrong, but I will try to answer it.

This appears to be asking: "Simplify J plus 16-148 plus 4."

To simplify...

J + 16 - 148 + 4

... it would be J plus the addition of the three numbers 16, (-148), and 4.

16 + (-148) + 4 = ( - 128 )

so the answer is...

J - 128

Q: J plus 16-148 plus 4

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4

It's an algebraic expression that can be simplified to: j-128

There are no brackets!

(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)

2j+1/j+5 = 1 Multiply all terms by j+5 to eliminate the fraction: 2j+1 = j+5 2j-j = 5-1 j = 4

Related questions

4

It's an algebraic expression that can be simplified to: j-128

There are no brackets!

(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)

j

2j+1/j+5 = 1 Multiply all terms by j+5 to eliminate the fraction: 2j+1 = j+5 2j-j = 5-1 j = 4

-19+j

#include <iostream> int main() { int i,j; for(i=1;i<6;i++) // Change 6 to a higher number to get more lines of output { for(j=i;j<i+4;j++) // Change 4 to a higher number to get more numbers in each line cout<<j; cout<<"\n"; } return 0; }

-4 (9j+5) = -36 j - 20 or - (36j + 20)

Reading plus level j answers

Ctrl plus J is used to justify text or a paragraph.

e must be 0, j can be anything