I am concerned that this question [ J plus 16-148 plus 4? ] was typed wrong, but I will try to answer it.
This appears to be asking: "Simplify J plus 16-148 plus 4."
To simplify...
J + 16 - 148 + 4
... it would be J plus the addition of the three numbers 16, (-148), and 4.
16 + (-148) + 4 = ( - 128 )
so the answer is...
J - 128
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4
It's an algebraic expression that can be simplified to: j-128
There are no brackets!
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
2j+1/j+5 = 1 Multiply all terms by j+5 to eliminate the fraction: 2j+1 = j+5 2j-j = 5-1 j = 4