I am concerned that this question [ J plus 16-148 plus 4? ] was typed wrong, but I will try to answer it. This appears to be asking: "Simplify J plus 16-148 plus 4." To simplify... J + 16 - 148 + 4 ... it would be J plus the addition of the three numbers 16, (-148), and 4. 16 + (-148) + 4 = ( - 128 ) so the answer is... J - 128
4
There are no brackets!
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
2j+1/j+5 = 1 Multiply all terms by j+5 to eliminate the fraction: 2j+1 = j+5 2j-j = 5-1 j = 4
I am concerned that this question [ J plus 16-148 plus 4? ] was typed wrong, but I will try to answer it. This appears to be asking: "Simplify J plus 16-148 plus 4." To simplify... J + 16 - 148 + 4 ... it would be J plus the addition of the three numbers 16, (-148), and 4. 16 + (-148) + 4 = ( - 128 ) so the answer is... J - 128
4
Designate the number of wrong sums for each person by the first letter of their names, c, j, and w. From the statement of the problem, c = j + 4, w = c + 4 = j + 4 + 2 = j +6, and c + j + w = 16. Substituting for c and w in terms of j: (j + 4) + j + (j + 6) = 16, or 3j + 10 = 16, or 3j = 6, or j = 6/3 = 2.
148 and u r dumb
T-J- Hooker - 1982 Love Story 4-16 was released on: USA: 16 February 1985
There are no brackets!
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
j
2j+1/j+5 = 1 Multiply all terms by j+5 to eliminate the fraction: 2j+1 = j+5 2j-j = 5-1 j = 4
-19+j
#include <iostream> int main() { int i,j; for(i=1;i<6;i++) // Change 6 to a higher number to get more lines of output { for(j=i;j<i+4;j++) // Change 4 to a higher number to get more numbers in each line cout<<j; cout<<"\n"; } return 0; }
16