2 adults and 5 children.
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Assuming the processing fee is £3.00 One ticket = £19.95 + £3.00 = £22.95 Two tickets = (19.95 x 2) + 3.00 = £42.90 Five tickets = (19.95 x 5) + 3.00 = £102.75 And so on ...
s- student, price of ticket is $2 a- adult, price for ticket i s$ 3 2*s money collected from students 3*s money collected from adults if a+s=400 and 3*a+2*s=1050 we have system of linear equations so a=400-s substitute in second equation a with 400-s then 3*(400-s) +2*s=1050 1200-3*s +2s=1050 1200 - s = 1050 -1200 -1200 -s = - 150 s=150 if s=150 then a=400-s so a=400-150, thus a=250 At the game sold 250 adult tickets and 150 student tickets
10 adults & 10 children's
It costs 15.00 for two adults and two children.
The formula to determine the total money is nA + mC = 1317.50 where n is the number of adult tickets sold and A is the price of the adult tickets and m OS the number of child tickets and C is the price of a child ticket. Substituting in the actual prices we get... eq 1. n*7.50 + m * 3.50 = 1317.50 eq 2. n+m = 205 rearranging eq 2 we get n = 205 - m substituting this into eq 1 we get.. (205 -m) * 7.5 + m * 3.5 = 1317.50 Simplifying we get 1537.5 - 7.5m + 3.5m = 1317.50 1537.5 - 1317.5 = 4m 220 = 4m 55 = m substituting into eqn 2 we get n + 55 = 205 n = 150. Therefor 150 Adult tickets were sold 55 Child tickets were sold