It costs 15.00 for two adults and two children.
10 adults & 10 children's
I'll try to explain it.We know that an adult's ticket is two times the cost of a child's ticket. We will call the child's ticket "y". If we do so, the adult's ticket will be 2"y" because it's two times the cost of a child's ticket. We also know that the total cost is 28. Now, we'll write an equation, knowing the number of children and adults and the relationship between the costs:2*2y will be the two adult's tickets.3*y will be the three children's tickets.The equation:2*2y+3*y=284y+3y=287y=28y=4Now, we know that ONE child's ticket costs 4. To find out how much an adult's ticket costs, we have to double it (look at the exercise, it says that an adult's ticket is two times the cost of a child's ticket).4*2=8Finally, we've found out that a child's ticket costs 4 and an adult's ticket costs 8.We can check it as well:2*8+3*4=16+12=28
2 adults and 5 children.
A plane ticket call C dollars for an adult and D dollars for a child find the expression that represents the total cost for 5 adults and 4 children
Sounds like a system of equations. X = adult ticket Y = student ticket Change all to pennies for convenience. X + Y = 105 300X + 150Y = 25000 -150(X + Y = 105) - 150X - 150Y = - 15750 300X + 150Y = 25000 -----------------------------------add them 150X = 9250 X = 62 adult tickets ------------------------ Y = 43 student tickets -------------------------- Those two prices added together = $250.50 So, we are a little off. I rounded the adult ticket number, but pieces of tickets can not be sold, so check work.
10 adults & 10 children's
$5/person or if it is cheaper for you $17 for a fun pass A fun pass includes 2 adults tickets and 4 children tickets or 1 adult ticket and 5 children tickets
20 they bought 20 tickets for both adults and children
I'll try to explain it.We know that an adult's ticket is two times the cost of a child's ticket. We will call the child's ticket "y". If we do so, the adult's ticket will be 2"y" because it's two times the cost of a child's ticket. We also know that the total cost is 28. Now, we'll write an equation, knowing the number of children and adults and the relationship between the costs:2*2y will be the two adult's tickets.3*y will be the three children's tickets.The equation:2*2y+3*y=284y+3y=287y=28y=4Now, we know that ONE child's ticket costs 4. To find out how much an adult's ticket costs, we have to double it (look at the exercise, it says that an adult's ticket is two times the cost of a child's ticket).4*2=8Finally, we've found out that a child's ticket costs 4 and an adult's ticket costs 8.We can check it as well:2*8+3*4=16+12=28
2 adults and five children
2 adults and 5 children.
Toddlers - $15 Children - $33 Adults - $43 Family 2 children + 2 adults = $130 Family 1 adult +3 children = $130
2 adults, 6 students 4 adults, 3 students 6 adults 9 students 4 combinations
Something is wrong with the math here, if you sold each ticket for only a dollar each, you should have at least 500 dollars but you only have 475. I think someone is flagrantly skimming money in your boxoffice.
A child's ticket is 87.33 and an adult ticket is 78.81 but it depends on how many days you stay and how many children and adults you have
7 Adult tickets 13 Child tickets
325 Tickets sold to adults 400 tickets sold to students