9,998,244
9,999,999 (almost 10 million)
97
1010111 1111100 1011101 and many more
It is 63.
9,998,244
take away the s
9,999,999 (almost 10 million)
97
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
The smallest positive 4-digit multiple of seven is 1,001.
666 - which in base 10 would be 294+42+8=344
1010111 1111100 1011101 and many more
It is 63.
1 The largest five-digit number is 99999 and the smallest six-digit number is 100000, so the difference is one. If you're just looking for an answer to a homework question, that's all you need. For the brainy: Suppose the answer was greater than one. That would mean that there are one or more numbers between the largest five-digit number and the smallest six-digit number that cannot be written with either five or six digits. Either they would have to be written with four or fewer digits, which would make them smaller than any five-digit number, or with seven or more digits, which would make them larger than any six-digit number. If the answer was less than one, it would mean that it would be possible to have a five digit number that was greater than a six-digit one. So the answer must be one.
the biggest number is 9999999.
9,999,876 is the greatest seven-digit number using four different digits.