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lim (x3 + x2 + 3x + 3) / (x4 + x3 + 2x + 2)

x > -1

From the cave of the ancient stone tablets, we cleared away several feet of cobwebs and unearthed

"l'Hospital's" rule: If substitution of the limit results in ( 0/0 ), then the limit is equal to the

(limit of the derivative of the numerator) divided by (limit of the derivative of the denominator).

(3x2 + 2x + 3) / (4x3 + 3x2 + 2) evaluated at (x = -1) is:

(3 - 2 + 3) / (-4 + 3 + 2) = 4 / 1 = 1

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15y ago

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