midpoint: (x1+x2/2 , y1+y2/2) quadratic: -b plus or minus square root b squared minus 4ac divided by 2a
Right, 3x-4x+9x-x1. 3x - x = 2x2. 9x-4x = 5x- 2x +5x = 7x
Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared
4
it divides theline segment..xDusing midpoint formula..and division of line segment formula..m=(X1+X2)/2 (Y1+Y2)/2X=X1+r(X2-X1)xD ..
it equals x1 it equals x1
Oh honey, you've got yourself a classic case of finding the average of two points in a coordinate plane. All you need to do is add the x-coordinates (x1 + x2) and divide by 2 to get the x-coordinate of the midpoint. Then do the same for the y-coordinates (y1 + y2), divide by 2, and voila, you've got the y-coordinate of the midpoint. Easy peasy lemon squeezy!
The answer is: X1 = 2 X2 = -7
midpoint: (x1+x2/2 , y1+y2/2) quadratic: -b plus or minus square root b squared minus 4ac divided by 2a
2x2+7/x1
A set of numbers will have a mean, which is defined as the sum of all the values divided by the number of values. Suppose this mean is m. For each of the values, the squared deviation is the square of the difference between that value and m. Algebraicly, if you have a set {x1, x2, x3, ... , xn}, whose mean is m, then the squared deviation from the mean for x1 is (x1 - m)2.
x²+2x-15=0 x1=-2/2 - Square root of ((2/2)²+15) x1=-1-4 x1=-5 x2=-2/2 + Square root of ((2/2)²+15) x2=-1+4 x2=3
The degree of the polynomial 2x + 5 is 1. The highest power of x is x1, i.e. 2x1 + 5x0, hence the designation of first degree.
Right, 3x-4x+9x-x1. 3x - x = 2x2. 9x-4x = 5x- 2x +5x = 7x
Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared
square root(x2-x1)squared+(y2-y1)squared
4