If line BE is the bisector of segment AC, it means that BE divides AC into two equal segments. Therefore, if AB is 7, then AC must be twice that length, making AC equal to 14.
If line BE is the bisector of segment AC, it means that it divides AC into two equal parts. Given that AB is 7 units, it implies that the length of AC is twice the length of AB. Therefore, AC is 2 × 7 = 14 units.
AB plus BC equals AC is an example of the Segment Addition Postulate in geometry. This postulate states that if point B lies on line segment AC, then the sum of the lengths of segments AB and BC is equal to the length of segment AC. It illustrates the relationship between points and segments on a line.
The answer is "No Solution" because there is not enough information.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
The symbol for an angle bisector is typically represented by a ray or line segment that divides an angle into two equal parts. In geometric notation, it may be denoted as ( \overline{AD} ) if ( D ) is the point on the angle's interior where the bisector intersects. Additionally, the angle bisector is often associated with the notation ( \angle ABC ) where ( D ) lies on the ray ( \overline{AC} ), indicating that ( \overline{AD} ) bisects ( \angle ABC ).
14
If line BE is the bisector of segment AC, it means that it divides AC into two equal parts. Given that AB is 7 units, it implies that the length of AC is twice the length of AB. Therefore, AC is 2 × 7 = 14 units.
If 2 segments have the same length they are known as 'congruent segments' IE: segment AB=segment AC (or AB=AC) then AB @ AC (or AB is congruent to AC)
segment ac
The answer is "No Solution" because there is not enough information.
To find the length of segment AB, we can use the segment addition postulate, which states that the total length of a segment is equal to the sum of the lengths of its parts. Therefore, AB + BC = AC. Given that AC = 78 mm and BC = 29 mm, we can substitute these values into the equation to find AB: AB + 29 = 78. Solving for AB, we get AB = 78 - 29 = 49 mm.
Ab+bc=ac
Since B is located between A and C, you can just add the two lengths together, so AC = m + n.your segment looks like this:A----B----Cwhere AB=m, BC=n, and AC=m+n
Usually a line segment in a triangle is either assigned a letter, or is referred to by the letters at the end of the segment with a line overhead. For instance, if you have a triangle ABC, you'll have segments AB, AC, and BC. And there would be a line over each segment name.
Let D represent the point on BC where the bisector of A intersects BC. Because AD bisects angle A, angle BAD is congruent to CAD. Because AD is perpendicular to BC, angle ADB is congruent to ADC (both are right angles). The line segment is congruent to itself. By angle-side-angle (ASA), we know that triangle ADB is congruent to triangle ADC. Therefore line segment AB is congruent to AC, so triangle ABC is isosceles.
If AC plus CB equals AB and AC is equal to CB, then point C is the midpoint of segment AB. This means that point C divides the segment AB into two equal parts, making AC equal to CB. Therefore, point C is located exactly halfway between points A and B.
Let us consider a line l such that it is the perpendicular bisector of line segment AB and the line intersects at point C.Let us take any point on line l(say, D). Join A to D and B to D.Now we have two triangles ACD and BCD.Now, in triangles ACD & BCD, we haveCD = CD (Common side)�ACD = �BCD (Right angle)AC = BC (Since l bisects AB)According to Side-Angle-Side criteria: Both triangles are congruent.Since both triangles are congruent, therefore AD = BD.So, l is the set of all points equidistant from A & B.Hence proved.