0
Add your answer:
Earn +20 pts
How do you solve a to the power of m times a to the power of n?
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
What does m equals in mn equals m plus n?
m = n/(n-1)
How can you print 5 54 543 5432 54321?
in PHP: for($n = 5; $n >= 1; $n--){ for($m = 5; $m >= $n; $m--){ echo $m; } echo " "; }
Can you prove mathematically that a geometric random variable possesses the so called Memory-less property?
Proof: P{T>n+m/T>n}=P{T>n+m,T>n}/P{T>n} (Bayes theorem) =P{T>n+m}/P{T>n} =((1-p)^(n+m))/(1-p)^n = (1-p)^(n+m-n) = (1-p)^m (1-p)^m = {T>m} So T>m has the same probability as T>m+n given that T>n, which means it doesn't care (or don't remember) that n phases had passed.
How many one one functions are defined from a set having n elements to a set having m elements?
None if n > m n! if n = m and mPn = m!/(m-n)! where k! denotes 1*2*...*k
Where m and n are statements m n is called the of m and n?
Where m and n are statements m n is called the _____ of m and n.
How do you solve a to the power of m times a to the power of n?
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
What is the opposite of m-n?
The additiove opposite is -m+n or n-m. There is also a multiplicative opposite, which is 1/(m-n)
What is m x n?
m *n (m multiplied by n) would be mn.
What is the difference of m and n?
the double of n is m. is the difference between m and n
What does m equals in mn equals m plus n?
m = n/(n-1)
What is the opposite of this polynomial m - n?
-m+n
Who is M in Pokemon White?
There is no M there is a N but there is a N.
M times N equals 6300 if m and n are 2 digit multiples of 10 what could m and n be?
m and n are 70 and 90
How can you print 5 54 543 5432 54321?
in PHP: for($n = 5; $n >= 1; $n--){ for($m = 5; $m >= $n; $m--){ echo $m; } echo " "; }
Can you prove mathematically that a geometric random variable possesses the so called Memory-less property?
Proof: P{T>n+m/T>n}=P{T>n+m,T>n}/P{T>n} (Bayes theorem) =P{T>n+m}/P{T>n} =((1-p)^(n+m))/(1-p)^n = (1-p)^(n+m-n) = (1-p)^m (1-p)^m = {T>m} So T>m has the same probability as T>m+n given that T>n, which means it doesn't care (or don't remember) that n phases had passed.
Do red m-n-m's really give you cancer?
Do red m-n-m's really give you cancer Do red m-n-m's really give you cancer
