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What does m equals in mn equals m plus n?
m = n/(n-1)
How can you print 5 54 543 5432 54321?
in PHP: for($n = 5; $n >= 1; $n--){ for($m = 5; $m >= $n; $m--){ echo $m; } echo " "; }
Can you prove mathematically that a geometric random variable possesses the so called Memory-less property?
Proof: P{T>n+m/T>n}=P{T>n+m,T>n}/P{T>n} (Bayes theorem) =P{T>n+m}/P{T>n} =((1-p)^(n+m))/(1-p)^n = (1-p)^(n+m-n) = (1-p)^m (1-p)^m = {T>m} So T>m has the same probability as T>m+n given that T>n, which means it doesn't care (or don't remember) that n phases had passed.
How many one one functions are defined from a set having n elements to a set having m elements?
None if n > m n! if n = m and mPn = m!/(m-n)! where k! denotes 1*2*...*k
What are the different law of exponent?
Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.
Where m and n are statements m n is called the of m and n?
Where m and n are statements m n is called the _____ of m and n.
What is the opposite of m-n?
The additiove opposite is -m+n or n-m. There is also a multiplicative opposite, which is 1/(m-n)
What is m x n?
m *n (m multiplied by n) would be mn.
What is the difference of m and n?
the double of n is m. is the difference between m and n
What does m equals in mn equals m plus n?
m = n/(n-1)
What is the quotient of m and n?
You can write this as:m/nor "m" on top of "n", with a horizontal line separating them, like this:m---n
What is the opposite of this polynomial m - n?
-m+n
Who is M in Pokemon White?
There is no M there is a N but there is a N.
M times N equals 6300 if m and n are 2 digit multiples of 10 what could m and n be?
m and n are 70 and 90
How can you print 5 54 543 5432 54321?
in PHP: for($n = 5; $n >= 1; $n--){ for($m = 5; $m >= $n; $m--){ echo $m; } echo " "; }
Can you prove mathematically that a geometric random variable possesses the so called Memory-less property?
Proof: P{T>n+m/T>n}=P{T>n+m,T>n}/P{T>n} (Bayes theorem) =P{T>n+m}/P{T>n} =((1-p)^(n+m))/(1-p)^n = (1-p)^(n+m-n) = (1-p)^m (1-p)^m = {T>m} So T>m has the same probability as T>m+n given that T>n, which means it doesn't care (or don't remember) that n phases had passed.
Do red m-n-m's really give you cancer?
Do red m-n-m's really give you cancer Do red m-n-m's really give you cancer
