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You don't solve it!!! It is a method of manipulation of indices.
a^(n) X a^(m) = a^(n+m)
Similarly,
a^(n) / a^(m) = a^(n-m)
[a^(n)]^(m) = a^(nm)
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What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
What is the hardest math question ever?
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42
How can you solve m-4n equals 8?
m=16, n=2
What is the power of a matrix?
If n is a natural number and M is a matrix, then Mn denotes the matrix M multiplied by itself n times. We can include n=0, but that is just the identity matrix. So the power of a matrix is very similar to the exponents that are used for numbers.
How do you solve m²-n²196?
I'm assuming you meant m2-n2+196 m2-n2=-196 m2=-196+n2 m=14i+n n=m-14i
