0
You don't solve it!!! It is a method of manipulation of indices.
a^(n) X a^(m) = a^(n+m)
Similarly,
a^(n) / a^(m) = a^(n-m)
[a^(n)]^(m) = a^(nm)
What else can I help you with?
What is 3 to the 3rd power times 3 to the 2nd power?
To solve (3^3 \times 3^2), you can use the property of exponents that states (a^m \times a^n = a^{m+n}). Therefore, (3^3 \times 3^2 = 3^{3+2} = 3^5). Calculating (3^5) gives you (243).
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
What is the five law of exponents?
The five laws of exponents are: Product of Powers: ( a^m \times a^n = a^{m+n} ) — When multiplying like bases, add the exponents. Quotient of Powers: ( \frac{a^m}{a^n} = a^{m-n} ) — When dividing like bases, subtract the exponents. Power of a Power: ( (a^m)^n = a^{m \times n} ) — When raising a power to another power, multiply the exponents. Power of a Product: ( (ab)^n = a^n \times b^n ) — Distribute the exponent to each factor inside the parentheses. Power of a Quotient: ( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ) — Distribute the exponent to the numerator and denominator.
What is the hardest math question ever?
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42
How can you solve m-4n equals 8?
m=16, n=2
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
What is M to the fourth power Times n to the fourth power?
m4n4
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
K+m+n=1500M is three times as big as NK is twice as big as nCalculate k, m and n?
The equation given is not enough to solve for k, m, and n as it has 3 unknowns and only 1 equation. You need at least 2 or more equations to solve for the unknowns.
What is the hardest math question ever?
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
How can you solve m-4n equals 8?
m=16, n=2
The sum of 3 times m and n?
the sum of 3 times m and n
What do they mean by a to the b power times a to the c power equals a b c power?
ab*ac=ab+c consider the powers of 2. 22=4, 23=8, 22*23=32=23+2=25 when multiplying a number by itself, you raise its power by one. when multiplying a number by itself n times, you raise it to the power of n, so if you raise a number to the power n, then the seame number to the power m, then multiply these together you are multiplying n+m times
How do you solve L equals 2M plus 2N for N?
N=l-m
What are m and n when 4 over n times 9 times 2 over 9 whole thing powered n minus 2 times x power 6 minus 2n equals m over x power 2?
[(4/n)(9)(2/9)]^n -2x^6 - 2n=m/x^2 (8/n)^2 - 2x^6 -2n=m/x^2 (64x^2)/n^2 -2x^8 -2nx^2=m Now we know what m equals. I've got to go now. Sorry!
How do you solve m to the power 4 plus n to the power 4?
There isn't a solution to this as it's not a question or a problem, simply an expression. If you want to do something with it you'll need to specify what that is.
