n2 = 20 + n so n2 - n - 20 = 0 that is (n - 5)(n + 4) = 0 so that n - 5 = 0 or n + 4 = 0 n = 5 or n = -4
n2 = 10n + 56 Subtract (10n + 56) from each side: n2 - 10n - 56 = 0 Now you have something on the left side that you can factor: (n - 14) (n + 4) = 0 n = +14 n = - 4
Yes because if 1+0=1 than 0 plus b equals b
x = y = 0 ?
many solutions
n2 = 20 + n so n2 - n - 20 = 0 that is (n - 5)(n + 4) = 0 so that n - 5 = 0 or n + 4 = 0 n = 5 or n = -4
n2 - 10n + 21 = 0 Two numbers that sum to -10 and multiply to 21 are -3 and -7 So (n - 3)*(n - 7) = 0
(n + 4)(n - 4)
n2 = 10n + 56 Subtract (10n + 56) from each side: n2 - 10n - 56 = 0 Now you have something on the left side that you can factor: (n - 14) (n + 4) = 0 n = +14 n = - 4
Yes because if 1+0=1 than 0 plus b equals b
A=0 b=0 c=0
No.
x = y = 0 ?
many solutions
It equals 7
equation works for n = 0 and n = 1 as factors are n and n - 1
It equals 6