Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please edit your question to include words for symbols and resubmit.
There is no symbol between a and b.
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
I assume that with n(...) you mean the size of the set. It sure can; but it need not be.
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
n plus 15.n plus 15.n plus 15.n plus 15.
No, the equation m + n = n + m does not represent the distributive property. The distributive property is typically written as a(b + c) = ab + ac, where a, b, and c are numbers. It describes the relationship between multiplication and addition. The equation m + n = n + m is known as the commutative property of addition, which states that the order of addition does not affect the sum.
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
Yes. Matrix addition is commutative.
I assume that with n(...) you mean the size of the set. It sure can; but it need not be.
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
#include<iostream> int main() { std::cout << "Truth table for AND gate\n\n"; std::cout << " |0 1\n"; std::cout << "-+---\n"; for (unsigned a=0; a<2; ++a) { std::cout << a << '|'; for (unsigned b=0; b<2; ++b) { std::cout << (a & b) << ' '; } std::cout << '\n'; } std::cout << std::endl; }
n plus 15.n plus 15.n plus 15.n plus 15.
4b.
No, the equation m + n = n + m does not represent the distributive property. The distributive property is typically written as a(b + c) = ab + ac, where a, b, and c are numbers. It describes the relationship between multiplication and addition. The equation m + n = n + m is known as the commutative property of addition, which states that the order of addition does not affect the sum.
They have n in common.
4b
∫ f'(x)(af(x) + b)n dx = (af(x) + b)n + 1/[a(n + 1)] + C C is the constant of integration.
If A and B are multiples of C, then A + B is also a multiple of C: If A is a multiple of C then A = mC for some integer m If B is a multiple of C, then B = nC for some integer n → A + B = mC + nC = (m + n)C = kC where k = m + n and is an integer → A + B is a multiple of C