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How do you expand binomials A plus b to the degree of n?
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
Why cant n(AUB) equal to n(a) plus n(b) in math?
I assume that with n(...) you mean the size of the set. It sure can; but it need not be.
According to the Boolean algebra 1 plus A plus B plus C is equal to?
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
Which expression models the phrase 15 greater than a number n plus 15 15 plus n n-15 plus n?
n plus 15.n plus 15.n plus 15.n plus 15.
Simplify b plus b plus b plus b?
4b
