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There is no symbol between a and b.

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Q: N plus a b
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Related questions

How do you expand binomials A plus b to the degree of n?

It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]


If properties of matrix addition let A B C D the m n matrix then 1 A plus B B plus A?

Yes. Matrix addition is commutative.


Why cant n(AUB) equal to n(a) plus n(b) in math?

I assume that with n(...) you mean the size of the set. It sure can; but it need not be.


According to the Boolean algebra 1 plus A plus B plus C is equal to?

1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.


Could you write the program that display truth table of AND gate by using C plus plus programming language?

#include<iostream> int main() { std::cout << "Truth table for AND gate\n\n"; std::cout << " |0 1\n"; std::cout << "-+---\n"; for (unsigned a=0; a<2; ++a) { std::cout << a << '|'; for (unsigned b=0; b<2; ++b) { std::cout << (a & b) << ' '; } std::cout << '\n'; } std::cout << std::endl; }


Which expression models the phrase 15 greater than a number n plus 15 15 plus n n-15 plus n?

n plus 15.n plus 15.n plus 15.n plus 15.


What is b plus b plus b plus b?

4b.


Is m plus n equals n plus m disributive property?

No, the equation m + n = n + m does not represent the distributive property. The distributive property is typically written as a(b + c) = ab + ac, where a, b, and c are numbers. It describes the relationship between multiplication and addition. The equation m + n = n + m is known as the commutative property of addition, which states that the order of addition does not affect the sum.


What do these expressions have in common - n plus 2 n plus 3 n-1 n plus 6 n plus 10?

They have n in common.


What is b plus b plus b plus b equals?

4b


Simplify b plus b plus b plus b?

4b


What is the integral of the derivative with respect to x of the function f multiplied by the quantity a times f plus b raised to the power of n with respect to x?

∫ f'(x)(af(x) + b)n dx = (af(x) + b)n + 1/[a(n + 1)] + C C is the constant of integration.