They have n in common.
Suppose X1 = N1/D1 and X2 = N2/D2 are two rational expressions, where the numerators N1 and N2 and denominators D1 and D2 are simpler expressions. Then X1 * X2 = (N1*N2)/(D1*D2) and X1 / X2 = (N1*D2)/(D1*N2).
The sum of the first 10 positive integers, using the formula N1 + (N1 + 1) + ... + N2 = N2 * (N2 + 1) / 2 - (N1 - 1) * N1 / 2 is: 55
The N1 is a rocket.
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
#declare value of product product = 0 #while loop in python #while (test condition) : # statements (s) while product < 100: #prompt for a user to enter a number n1 = input ("Enter a number: ") #multiply n1 times 10 product = n1 * 10
the value of the exponent n1
the value of the exponent n1
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2-1) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
void main() { int i; float n1,n2; abc: printf("Enter two nos "); scanf("%f%f",&n1,&n2); printf("\n %f + %f = %f " ,n1,n2,n1+n2); printf("\n %f - %f = %f " ,n1,n2,n1-n2); printf("\n %f x %f = %f " ,n1,n2,n1*n2); printf("\n %f / %f = %f " ,n1,n2,n1/n2); printf("\npress 5 to make another calculation"); scanf("%d",&i); if (i==5) goto abc; }
what are the price of a movie ticket at N1 city
The ground state of an atom is when n1, not n0.