Radius = 1111
x2+3=124 x2=121 x= square root(121) x=11
Centre = (0,0), the origin; radius = 11
If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2
174
The discriminant is 0.
Radius = 1111
x2+3=124 x2=121 x= square root(121) x=11
Centre = (0,0), the origin; radius = 11
If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2
121
174
It is B, 0.
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
Negative 17 plus 121 divided by 8 equals 13.
The discriminant is 121.
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0