You can't do that because 12 plus 60 plus 61 equals 173 unless yo take out the twelve but if you can only use the given variables then you cant do that
Radius = 1111
x2+3=124 x2=121 x= square root(121) x=11
Centre = (0,0), the origin; radius = 11
If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2
174
The discriminant is 0.
Radius = 1111
x2+3=124 x2=121 x= square root(121) x=11
Centre = (0,0), the origin; radius = 11
If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2
121
174
It is B, 0.
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
Negative 17 plus 121 divided by 8 equals 13.
The discriminant is 121.
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0