(-1)2=1 all squared numbers turn out positive and 12=1 (-1)2=1 all squared numbers turn out positive and 12=1
if you take your time youll figure out its e=mc2
1
(x2y2)3 + (x3y3)2 = 2x6y6.
you distribute the negative to the inside of the parenthesis
No, it is not. To be correct, the expression requires parenthesis, which are missing.
Because in parenthesis you have to multiply it by something.
if you take your time youll figure out its e=mc2
x cubed y cubed z squared
It's hard to be sure that I definitely understand the question. Let's see if this helps: (122) = 144, so -(122) = -144 (-122) = 144, so -(-122) = -144
1
(x2y2)3 + (x3y3)2 = 2x6y6.
(-5)-2 = 1/(-5)2 = 1/25 = 0.04
you distribute the negative to the inside of the parenthesis
-1
75r^2-48 You can take out 3.So... 3(25r^2-16) 3-parenthesis-25r squared-minus-16-parenthesis (:
it equals positive one. one squared is always one. if they're both negative, negative times negative is always positive.
-3^2 = -9, It is -3 x 3 = -9, unless its in parenthesis, which would be (-3)^2, this equation is -3 x -3, which equals 9. Since a negative and a negative in multiplication is always positive.9