15y2 + 45y - 9 = 4y - 5y2; thus, 20y2 + 41y - 9 = (5y - 1)(4y + 9) = 0. Therefore, the solution to the equation given is, y = 1/5 or -2¼.
YES : Equation (1) 5x - y = 3x + 9y = 19 : Multiply by 5 →Equation (2) 5x + 45y = 95Subtract Equation (1) from Equation (2) to eliminate 'x' terms. This gives : 45y -(-y) = 95 - 3 : 46y = 92 : y = 2Substituting for y in Equation(1) gives : 5x - 2 = 3 : 5x = 3 + 2 = 5 : x = 1Substituting for x and y in the equation 3x + 4y - 6c = -7 gives : 3 + 8 - 6c = -7 : 6c = 11 + 7 = 18 : c = 3
45y+5-13=143 45y-8=143 45y=151 y=151/45
15y2 + 45y - 9 = 4y - 5y2; thus, 20y2 + 41y - 9 = (5y - 1)(4y + 9) = 0. Therefore, the solution to the equation given is, y = 1/5 or -2¼.
set up a system of equations x+y=45 xy=200 set one equal to a variable x=-y+45 plug it into the other equation y(-y+45)=200 distribute the y -y2+45y=200 set it equal to 0 -y2+45y-200=0 take out the negative -(y2-45y+200)=0 factors of 200 are 1&200, 2&100, 4&50, 5&40, 10&20 5 and 40 = 45 factor -(y-5)(y-40)=0 solve for y y=5,40 this is the proper way to do this or you could just guess and check hope i helped :)
The GCF is 5y.20y3 = (5y)(4y2)5y2 = (5y)(y)45y = (5y)(9)
3x - 5y = 45At the y-intercept, x = 0.-5y = 45y = -9At the x-intercept, y = 0.3x = 45x = 15
YES : Equation (1) 5x - y = 3x + 9y = 19 : Multiply by 5 →Equation (2) 5x + 45y = 95Subtract Equation (1) from Equation (2) to eliminate 'x' terms. This gives : 45y -(-y) = 95 - 3 : 46y = 92 : y = 2Substituting for y in Equation(1) gives : 5x - 2 = 3 : 5x = 3 + 2 = 5 : x = 1Substituting for x and y in the equation 3x + 4y - 6c = -7 gives : 3 + 8 - 6c = -7 : 6c = 11 + 7 = 18 : c = 3
Okay, I guess that the limitations of the WikiAnswers software prevented you from typing + and = signs, so I am guessing that the equations are as follows: (a) 5x + 11y = -2 (b) 2x + 9y = 13 Note: I have edited the question to coincide with equations (a) and (b). There are several ways to solve for x (and y). Multiply (a) by 2 and (b) by -5, so you now have: (a) 10x + 22y = -4 (b) -10x - 45y = -65 Now, add (a) and (b), being careful to keep the columns aligned. That yields: 0x - 23y = -69, which is (c) -23y = -69 Now, solve (c) for y by dividing both sides of the equation by -23. That leaves you with y = 3. Now that you have solved for y, you can substitute the value of y into either (a) or (b). Let's use (b) because that looks easier: 2x + 9y = 13 2x + 9(3) = 13 2x + 27 = 13 2x = -14 x = -7
1) x + y = -45 2) xy = -196 solve for x in equation 2 by dividing both sides by y x= -196/y plug this value for x into the first equation -196/y + y = -45 subtract y from both sides -196/y = -45-y multiply both sides by -y 196 =45y + y2 subtract 196 from both sides 0 = y2 + 45y - 196 factor 0 = (y + 49)(y - 4) set each factor equal to 0 y + 49 = 0, y = -49 y - 4 = 0, y = 4 y = -49 or 4 plug these values back into equation 1 x + 4 = -45, x = -49 x + -49 = -45, x = 4 so the two numbers are 4 and -49 As two numbers are required that sum to -45 and multiply to -196, start off by working out the prime factorization of 196: 196 = 2 x 2 x 7 x 7. Using this, pairs of factors of 196 can be calculated: 1 x 196 2 x 98 4 x 49 7 x 28 14 x 14 As -196 is required, one factor must be positive and the other negative which means when they are summed, really their difference is calculated: 1 x 196 - difference = 195 2 x 98 - difference = 96 4 x 49 - difference = 45 7 x 28 - difference = 21 14 x 14 - difference = 0 A difference of 45 means the factors are 4 and 49, but as -45 is required, the larger factor must be negative, meaning the required numbers are 4 and -49 If you are in fact trying to factor a quadratic equation x2 - 45x - 196 = 0, you could also use the quadratic formula [-b + or - the square root of (b2-4ac)] / 2a so [-(-45) + or - the square root of ((-45)2 - 4(1)(-196)] / 2(1) [45 + or - square root of (2809)] / 2 [45 + or - 53] / 2 45 + 53 = 98, divide by 2 = 49 45 - 53 = -8, divide by 2 = -4 so the roots are (x - 49)(x + 4) so x = {49, -4}
It probably meant to be a 6 or 7. Its on the top row. They might of accidentally pressed y. Well it depends where you found the questions! Do you have any more questions? If you do please put them here. I would love to answer your questions to show off my skill!!! Sorry, don't mean to brag do I? Besides I am only 10 years old. I love God. Do you? You really should because he made you and everything! He is the true God. He answers my prayers. I would never turn my back on God!!! He is a loving and caring God! He forgives me and washes my sin into the sea. I read the bible and see how wonderful he is. Sorry, this isn't anything to do with answering questions but you know I'd rather die knowing that God loves me and hes gonna take me to heaven even if he isn't real and he is. Dont laugh at him coz he made you! Bye!!!126-45y19 AnswerAfter having College Algebra I and II, and Statistics I and II, and Business Mathematics and Accounting -- I believe the problem is not stated correctly. You can make it 126=45y19 by moving things around--but still, there's no such thing as 45y19. It should be 45y and then + or times but using ()--etc. The problem is probably written down wrong.
Integer Damath: 2 , -5, 8 , -11 , -7 , 10 , -3 , 0 , 4 , -1 , 6 , -9 Rational Damath: 2/10 , -5/10 , 8/10 , -11/10 , -7/10 , 10/10 , -3/10 , 0 , 4/10 , -1/10 , 6/10 , -9/10 Radical Damath: 144\8 , 100\2 , -81\32 , -121\18 , 64\2 , 36\32 , -25\18 , -49\8 , 16\32 , 4\8 , -\8 , -9\2 \ = square root Polynomial Damath: 78xy2 , 66x2y , -45y , -55x , 36x2y , 28y , -15x , -21xy2 , 10y , 6x , -xy2 , -3x2y