15y2 + 45y - 9 = 4y - 5y2; thus,
20y2 + 41y - 9 = (5y - 1)(4y + 9) = 0.
Therefore, the solution to the equation given is,
y = 1/5 or -2¼.
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10y2 - 15y2 = -5y2
1/5y2+9
-5y2+3x+2y
That is the most simplifiable version of this equation.
If y = 2x+1 is a tangent line to the circle 5y^2 +5x^2 = 1 then the point of contact is at (-2/5, 1/5) because it has equal roots