Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 3 such that the first three numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example,
You want the next number to be 1? Then U(n) = (-20n^3 + 123n^2 - 214n + 171)/3
You want the next number to be 2? Then U(n) = (-13n^3 + 80n^2 - 139n + 112)/2You want the next number to be 11? Then U(n) = -7n^3 + 40n^2 - 70n + 56
You want the next number to be 101? Then U(n) = 10n^3 - 59n^2 + 112n - 43
The next number in the sequence would be 25.
The sequence of differences between consecutive numbers is 9, 1, -20, 9, 1. If this continues then the next difference is -20 and therefore the seventh number is -5. (15 - 20).
243
It is obvious that 7 is added to get the next number from the previous one.
35
25 is the next number that appears in that sequence.
The next number in the sequence would be 25.
The rule is 5 10 15 20 25 30 .... etc and accordingly the next number in the sequence will be 106
The sequence of differences between consecutive numbers is 9, 1, -20, 9, 1. If this continues then the next difference is -20 and therefore the seventh number is -5. (15 - 20).
The sequence of differences between consecutive numbers is 9, 1, -20, 9, 1. If this continues then the next difference is -20 and therefore the seventh number is -5. (15 - 20).
121.
243
Each is half of the previous number, so 6.25 will be next.
It is obvious that 7 is added to get the next number from the previous one.
35
This is a sequence of perfect squares. 12=1, 22=4, 32=9, 42=16, 52=25. The next number is 62=36.
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