Total possibilities of any 4 from 22 is (22 x 21 x 20 x 19)/(4 x 3 x 2) ie 7315.
Any 2 boys out of 8 is (8 x 7)/2 ie 28 and any 2 girls out of 14 is (14 x 13)/2 ie 91.
These pairs can be combined in 91 x 28 ways ie 2548 so probability of 2 & 2 is
2548 out of 7315 which is 0.35 all but a whisker!
There is only one girl out of 12 students so the probability that the girl is selected is 1/12.
Probability of picking a student is 800 / (800+50+150) = 800 / 1000 = .8.
1.6
The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.
The probability is indeterminate. I might ask a student or I might not.
The probability is 10 percent.
There is only one girl out of 12 students so the probability that the girl is selected is 1/12.
1/12 =0.08333... ≈ 8.3%
I think it depends on how many students are thinking of alphabet letters at the same time :) The first student will think of a letter from the English alphabet. Then, the second student will think of a letter. The probability that the second student will select what the first student selected is 1/26.
85/500 = 17%
The probability is the number of girls divided by the number of students, so 12/22, or 6/11
110
If there are 12 boys and 6 girls, the total number of students would be 18. You are looking for the probability of selecting a girl from the class: 6/18 Just reduce the fraction to its lowest form 6/18 = 2/6 = 1/3 Your answer would be 1/3.
3 students.
4 in 7 chance
50% of 12 male students = 6 25% of 4 female students = 1 So in total 7 students go for pizza. The probability that a randomly selected student will be female is 1/7 or 14%.
Probability of picking a student is 800 / (800+50+150) = 800 / 1000 = .8.