14 and 6
When one of the numbers is positive and the other is negative.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
That happens when only one of the two integers is negative.
They are 6, 8, 10 and 12.
When one factor is less than one, the product will be less than the other factor.
When one of the numbers is positive and the other is negative.
The numbers are 11, 13, 15 and 17.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
That happens when only one of the two integers is negative.
They are 6, 8, 10 and 12.
The integers are 5 and 7.
81
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
The product will be less than the other factor.
11, 13, 15 and 17(143 is 112 less than 255)The equation is (A)(A+2) = (A+4)(A+6) - 112A2 + 2A = A2 +10A +24 -1122A = 10A - 888A = 88A = 112,5,6
When one factor is less than one, the product will be less than the other factor.
When one of the factors is less than or equal to 1, and the other is positive. Examples: 1 x 9 = 9 0 x 5 = 0 -1 x 10 = -10 If both are negative, it doesn't work: -10 x -10 = +100