Well, honey, you can take 4 times 6, which equals 24, then add 7 to get 31. After that, multiply 31 by 2 to get 62. Finally, just add the remaining number 7 to get 69. Sorry, darling, but 69 is as close as you're gonna get to 100 with those numbers.
One way is: (4 + 4 + 6 + 9)^(100/50) = 23^2 = 529
To find how many numbers between 1 and 100 inclusive are divisible by 2, we can identify the even numbers in that range. The even numbers from 1 to 100 are 2, 4, 6, ..., 100. This forms an arithmetic sequence where the first term is 2, the last term is 100, and the common difference is 2. There are 50 even numbers (2, 4, 6, ..., 100), so there are 50 numbers between 1 and 100 that are divisible by 2.
Assuming this is mathematical style question from the first ever programme broadcast on Channel 4 where all 6 numbers do not have to be used: (100 + 9 + 2) x (3 + 4) = 111 x 7 = 777
1+2+3+4+5+6+7+(8x9)
As a product of its prime factors: 2*2*7*7 = 196
As a product of its prime factors: 2*2*5*5 = 100
As a product of its prime factors: 2*2*5*5 = 100
As a product of its prime factors: 2 * 2 * 5 * 5 = 100
2 x 2 x 5 x 5
2*(1+2+3+4)*5=100or (2+3)*(4*5)*1=5*20*1=100
One way is: (4 + 4 + 6 + 9)^(100/50) = 23^2 = 529
100 + 75 + 2 - 25 = 152 x 4 = 608 + 1 = 609. (Yes I have been on Countdown!)
To find how many numbers between 1 and 100 inclusive are divisible by 2, we can identify the even numbers in that range. The even numbers from 1 to 100 are 2, 4, 6, ..., 100. This forms an arithmetic sequence where the first term is 2, the last term is 100, and the common difference is 2. There are 50 even numbers (2, 4, 6, ..., 100), so there are 50 numbers between 1 and 100 that are divisible by 2.
2 + 8 = 10... 3 + 7 = 10... 6 - 4 = 2 10 x 10 = 100... 100 x 2 = 200That's assuming you don't have to use all the numbers !
The numbers that go into 52 are 1, 2, 4, 13, 26, and 52. The numbers that go into 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100. These numbers are known as factors, which are integers that can be multiplied together to give the original number.
Assuming this is mathematical style question from the first ever programme broadcast on Channel 4 where all 6 numbers do not have to be used: (100 + 9 + 2) x (3 + 4) = 111 x 7 = 777
The common factors are: 1, 2, 4