2a^3 + 54 can first be factored into 2 (a^3 + 27). This can then be factored out to 2 (a + 3) (a^2 - 3a + 9).
54
-51
(x - 6)(x + 9)
57
It is: 54*54 = 2916
x2 + 15x + 54 = (x + 6)(x + 9) or (x + 9)(x + 6) since 6*9 = 54 and 6 + 9 = 15However, commutativity is implicit in deriving this factorisation so that the two factorisations are the same.or factor by groupingx2 + 15x + 54= x2 + 6x + 9x + 54= (x2 + 6x) + (9x + 54)= x(x + 6) + 9(x + 6)= (x + 6)(x + 9)
11 + 694 - 54 + 497 + 54 = 1202
54 ÷ 6 + 36 + 9 = 54
54 + 3 + 10 = 67
It is: 126 plus 54 = 180
x2-15x+54 factor pairs of 54: 1,54 2,27 3,18 6,9 -1,-54 -2,-27 -3,-18 -6,-9 <-6 and -9 sum to -15 x2-6x - 9x+54 x(x-6) - 9(x-6) (x-6)(x-9)