Wiki User
∙ 9y agoA 2-foot border around a 20 x 14 area makes the area 24 x 18 making the perimeter 84 feet.
Wiki User
∙ 9y agoThe width is 4ft the length is 16ft
The width would be X, and the length 4 X. Since the perimeter of 40 ft is the two lengths, and the 2 ends, that would be X+X+4X+4X= 40 ft, or 10X= 40 ft, simplified by dividing both sides of the = by 10, to get X=4 and 4X=16.
If there's a two foot border around a 14 x 20 foot area, that makes it 18 x 24 feet, with a perimeter of 84 feet.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
Assuming you mean a rectangle: use the formula:p = 2(l+w) (i.e., perimeter equals twice length plus width). In this formula, replace p with the known perimeter, and l with the given length, then solve for width.
84
The width is 4ft the length is 16ft
If the side walk is 2ft wide then the total measurement of the area is 22 ft by 16 ft. [ 20 ft + 2 ft by 14 ft + 2 ft] the perimeter of the outside border of the sidewalk would be 44 ft + 32 ft [(22 ft x 2) + (16 ft x 2)] for a total of 76 ft.
The width would be X, and the length 4 X. Since the perimeter of 40 ft is the two lengths, and the 2 ends, that would be X+X+4X+4X= 40 ft, or 10X= 40 ft, simplified by dividing both sides of the = by 10, to get X=4 and 4X=16.
If there's a two foot border around a 14 x 20 foot area, that makes it 18 x 24 feet, with a perimeter of 84 feet.
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
22 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (4) + 2 (7) = 22
26 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (7) + 2 (6) = 26
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
Assuming you mean a rectangle: use the formula:p = 2(l+w) (i.e., perimeter equals twice length plus width). In this formula, replace p with the known perimeter, and l with the given length, then solve for width.
Length + length + width + width = perimeter. Length + width x 2 = perimeter