7/10
7/10
The probability of randomly choosing 1 blue sock is 7/10. The probability of randomly choosing 2 blue socks in a row is 7/10 x 7/10 = 49/100.
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
7/10
7/10
7/10
The probability of randomly choosing 1 blue sock is 7/10. The probability of randomly choosing 2 blue socks in a row is 7/10 x 7/10 = 49/100.
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
The probability is that it comes out 7 times out of 10 tries, or 70% of the times.
7/10
There are 10 numbers {1, 2, ..., 10} The solution set contains {4, 5, ...,10} - 7 numbers in total → probability = number of successful tries/total number of tries = 7/10 = 0.7
Probability, P, of 70% or more correct (7 or more correct) is: P(7) + P(8) + P(9) + P(10). See the related link; N=10, P = 0.5, and K = 7, 8, 9, & 10. Therefore the probability is: .11719 + .04395 + .00977 + .00098 = .17189 or approximately 17.2% probability 7 or more correct.
The probability will depend on the underlying distribution, which is not specified.
The probability is 21/36 = 7/12
depends on the numbers on the spinner. if 1 thru 10, 7/10
7/128, or about 5.5% The student has a 1/2 probability of getting each question correct. The probability that he passes is the probability that he gets 10 correct+probability that he gets 9 correct+probability that he gets 8 correct: P(passes)=P(10 right)+P(9 right)+P(8 right)=[(1/2)^10]+[(1/2)^10]*10+[(1/2)^10]*Combinations(10,2)=[(1/2)^10](1+10+45)=56/1024=7/128.