7/128, or about 5.5%
The student has a 1/2 probability of getting each question correct. The probability that he passes is the probability that he gets 10 correct+probability that he gets 9 correct+probability that he gets 8 correct:
P(passes)=P(10 right)+P(9 right)+P(8 right)=[(1/2)^10]+[(1/2)^10]*10+[(1/2)^10]*Combinations(10,2)=[(1/2)^10](1+10+45)=56/1024=7/128.
If an examination paper has 10 questions and consists of six question in algebra, the other four questions could be geometry, calculus, or trigonometry.
Since there are only two options for the answer, on average the student will answer half of the answers correctly.
P = (6!)/(6-4)!4!=15
Questions are more than one and question is one its not that difficult
If the question was -6xy = 0 - 6xy, then it is the additive identity property of 0. However, due to limitations of the browser used to post questions, most symbols are not visible to us. It is, therefore, difficult for me to be sure what your question was. Hoped I guessed correctly.
64/256
The answer to this question depends on how easy or difficult the eight questions are. If, for example, the questions were based on Godel's incompleteness theorem it is very likely that nobody could answer them - ever.
Probability questions are not all the same so there is not a single kind of answer: it depends on the nature of the question!
There is 1 right answer out of 5 possible answers, so the probability of guessing it correctly is 1/5 or 20% or 0.2.
who correctly answered to yaksha's question
You have a 4 percent chance of guessing both answers correctly assuming there is only one correct answer to each question and that you may only answer once per question.
you'd have a 50% chance of getting the 3rd and 4th question correct because you said the first 2 questions are already anwsered correctly :)
because anyone can answer a question.
45 were correctly answered
50:50
If I understand the question correctly, the answer is 3/10.
If I have understood the question correctly, the answer is 1/2.