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int factorial(int n) { int i; int f=1; for(i=2;i<=n;++i) f*=i; return f; }
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
The factorial of a number is the product of all the whole numbers, except zero, that are less than or equal to that number.
a factorial number is a number multiplied by all the positive integers i.e. 4!=1x2x3x4=24 pi!=0.14x1.14x2.14x3.14 0!=1
no answer....pls post
// constructor program to add two number's // program written by SuNiL kUmAr #include<iostream.h> #include<conio.h> class constructor { private: int a,b; public: constructor(int m,int n); int sum(); }; constructor::constructor(int m,int n) { a=m; b=n; } int constructor::sum() { int s; s=a+b; return (s); } int main() { int x,y; clrscr(); cout<<"enter two number's to add \n"; cin>>x>>y; class constructor k (x,y); cout<<"sum of two number's is = "<<k.sum(); getch(); return (0); }
factorial number Var num= prompt("enter any number "); Var i=1; Var fact=1; for(i=1;i
First of all we will define what factorial is and how to it is calculated.Factional is non negative integer. Notation would be n! It is calculated by multiplying all integers from 1 to n;For example:5! = 1 x 2 x 3 x 4 x 5 = 120.Note: 0! = 1Small C program that illustrates how factorial might be counted:#include int factorial(int num);int main() {int num;printf("Enter number: ");scanf("%d", &num);printf("Factorial: %d\n", factorial(num));return 0;}int factorial(int num) {if (num == 0) {return 1;}return num * factorial(num - 1);}Testing:Enter number: 5Factorial: 120Enter number: 0Factorial: 1
int factorial(int n) { int i; int f=1; for(i=2;i<=n;++i) f*=i; return f; }
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
#include <iostream> using namespace std; int main() { int i, number=0, factorial=1; // User input must be an integer number between 1 and 10 while(number<1 number>10) { cout << "Enter integer number (1-10) = "; cin >> number; } // Calculate the factorial with a FOR loop for(i=1; i<=number; i++) { factorial = factorial*i; } // Output result cout << "Factorial = " << factorial << endl;
' Iterative solution Function iterativeFactorial(ByVal n As Long) As Long Dim factorial As Long = 1 For i As Long = 1 To n factorial *= i Next Return factorial End Function ' Recursive solution Function recursiveFactorial(ByVal n As Long) As Long If n <= 1 Then Return n End If Return n * recursiveFactorial(n - 1) End Function
The time complexity for calculating the factorial of a number is O(n), where n is the number for which the factorial is being calculated.
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
/*program to calculate factorial of a number*/ #include<stdio.h> #include<conio.h> void main() { long int n; int a=1; clrscr(); printf("enter the number="); scanf("%ld",&n); while(n>0) { a*=n; n--; } printf("the factorial is %ld",a); getch(); }